With method please

Mathematics

1 answer:

IRINA_888 [86]3 years ago

6 0

Answer:

57.8º

Step-by-step explanation:

According to the law of sines $\frac{sinA}{a}$ = $\frac{sinb}{b}$ = $\frac{sinc}{c}$ .

In this triangle we have two sides with two of their angles.

Let's make 8 cm side a with 38º as its angle, and 11 cm side b with x as its angle.

$\frac{sinx}{11}$ = $\frac{sin38}{8}$

Now we multiply both sides by 11 to get rid of the denominator on the left.

sinx = $\frac{11sin38}{8}$

To find x, we use inverse sine.

x = sin⁻¹ (11sin38/8)

Plug this into a calculator, and you will get 57.837.

Round this to 57.8º

Hope this helps!

You might be interested in

Evaluate the integral by interpreting it in terms of areas Draw a picture of the region the integral

denis23 [38]

Answer:

Step-by-step explanation:

The picture is below of how to separate this into 2 different regions, which you have to because it's not continuous over the whole function. It "breaks" at x = 2. So the way to separate this is to take the integral from x = 0 to x = 2 and then add it to the integral for x = 2 to x = 3. In order to integrate each one of those "parts" of that absolute value function we have to determine the equation for each line that makes up that part.

For the integral from [0, 2], the equation of the line is -3x + 6;

For the integral from [2, 3], the equation of the line is 3x - 6.

We integrate then:

$\int\limits^2_0 {-3x+6} \, dx+\int\limits^3_2 {3x-6} \, dx$ and

$-\frac{3x^2}{2}+6x\left \} {{2} \atop {0}} \right. +\frac{3x^2}{2}-6x\left \} {{3} \atop {2}} \right.$ sorry for the odd representation; that's as good as it gets here!