All categories

2 years ago

If a bake sale is selling 3 cookies for $1.05, what is the price of one cookie?

Mathematics

2 answers:

kirill [66]2 years ago

8 0

Answer:

0.35

Step-by-step explanation:

if they have 3 cookies for $1.05 you would ÷ (devide) $1.05 by the amount of cookies (3) to find how much 1 cookie is worth. 1.05÷3=0.35

ElenaW [278]2 years ago

7 0

Answer: $0.35 which is the same as 35 cents

==========================================

Work Shown:

3 cookies = $1.05

3/3 cookies = $1.05/3

1 cookie = $0.35 = 35 cents

You might be interested in

Im having trouble on this

Degger [83]

Answer: girl no

Step-by-step explanation:

3 0

3 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

7 0

3 years ago

Which of the following are exterior angles? Check all that apply.

Leokris [45]

I will have you come in please thank you thank for you thank you
I miss my

4 0

4 years ago

Read 2 more answers

Pls help :)

Rufina [12.5K]

Answer:

need to get thoose 50 pints

Step-by-step explanation:

6 0

3 years ago

The police department wants to evaluate a new rule for vehicles that was put into place to prevent road accidents across all lar

Ainat [17]

<span>Option D. Total number of traffic accidents per year, by means of a bar chart that shows the difference of given values and that are represented by size, length and color. This to know the number of accidents that occur as first information. Also the option C. The decrease number of traffic accidents per year, the same with a bar chart that represents the data and its different results thrown. This is to determine the decrease, after knowing the annual number of accidents. This also helps to know the number of current accidents, increase, decrease and the main causes of accidents in large cities.</span>

3 0

4 years ago