No, because 8/10 and 2/5 both do not go into eachother equaly
So there are 44 people and in Tuesday, 3/4 I'd them stay overtime. In order to answer this divide 3 with 4 first into 0.75 in which you will multiply with 44
So the answer is 33, 33 people stayed over tine
Based on the problem above, the given values are as follows:
2:3:4 = Ratio of Millie, Josh and Libby's bonus
£105=Josh's share of the bonus
?=total amount of the bonus they shared.
In order to get this, we need to solve for Millie's and Libby's bonuses.
So to get Millie's share:
we do this.
2/3 : x/105. Cross multiply and divide and we get x=70. Therefore, Millie's share is £70.
Next is Libby's:
3/4 : 105/y. Cross multiply and divide and we get y=140. Therefore, Libby's share is £140.
Now, add up everything and we get £315. So the total amount of the bonus before they shared it is £315.
Answer:
x = 7, -1
Step-by-step explanation:
Use the formula (b/2)^2 in order to create a new term. Solve for x by using this term to complete the square.
The ∆ABC has been transformed to yield ∆A'B'C'. The fourth diagram shows that the transformation could NOT be achieved by rotation alone.
The diagram is attached with the answer below:-
<h3 /><h3>What is dilation?</h3>
Dilation is the process of increasing the size of an object while maintaining its shape. Depending on the scale factor, the object's size can be increased or decreased.
In the first figure, ∆ABC has been transformed to yield ∆A'B'C' by rotation of 180 degrees either clockwise or counterclockwise along the midpoint of AB.
The second and third figures are the same. In both figures, ∆ABC has been transformed to yield ∆A'B'C' by rotation of 180 degrees either clockwise or counterclockwise along with the origin.
In the fourth figure, ∆ABC has been transformed to yield ∆A'B'C' by rotation of 180 degrees either clockwise or counterclockwise along with the origin.
But only in the fourth figure, ∆ABC has been transformed to yield ∆A'B'C' by reflection along the x-axis.
Therefore, the correct option is the 4th diagram.
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