The answer 48cm but i can’t find no work for it if you haven’t got it already
Answer: Nazim have to pay $35 for 20 slices of pizza.
Monthly cost for x slices = 5+1.5x
Step-by-step explanation:
Let x = number of slices
As per given,
Total monthly cost for x slices = (membership cost) +(discounted price) ×(x)
i.e. Total monthly cost for x slices = 5+1.5x
If x=20
Then, Nazim have to pay = 5+1.5(20)
= 5+30= $35
i..e Nazim have to pay $35 for 20 slices of pizza.
Monthly cost for x slices = 5+1.5x
Answer:
The answer to the question is
The longest interval in which the given initial value problem is certain to have a unique twice-differentiable solution is (-∞, 4)
Step-by-step explanation:
To apply look for the interval, we divide the ordinary differential equation by (t-4) to
y'' +
y' +
y = 
Using theorem 3.2.1 we have p(t) =
, q(t) =
, g(t) = 
Which are undefined at 4. Therefore the longest interval in which the given initial value problem is certain to have a unique twice-differentiable solution, that is where p, q and g are continuous and defined is (-∞, 4) whereby theorem 3.2.1 guarantees unique solution satisfying the initial value problem in this interval.
Answer:
AAS
Step-by-step explanation:
Answer:
=18
Step-by-step explanation: