c. Deoxyribose:RNA I think that's right I hope it is I'm sorry if I got it wrong
Answer:
The correct answer is the formation of pyruvate from glucose willl be energetically less favorable.
Explanation:
According to the question matunt yeast has a shorter glycolytic pathay catalysing a follwing reaction
Glyceraldehyde-3-phosphate+H2O+NAD+ = 3-phosphoglycerate
So in the mutatant the formation of 1,3- bisphosphoglycerate is not occurring.The glyceraldehyde-3-phosphate is directly converted into 3-phosphoglycerate.
As a result the substrate level phosphorylation step that deals with formation of 3-phosphoglycerate from 1,3 bisphosphoglycerate is not occurring.
From this point of view it can be said that less energy will be formed in the mutant during glycolysis than that of normal one.
So the formation of pyruvate from glucose will be energetically less favorable.
Answer:
A: Unlike DNA, XNA replicates conservatively
Explanation:
<em>The replication of the DNA is </em><em>semi conservative.</em><em> This means that newly replicated double helix DNAs usually consist of one parental strands and one newly synthesized strands. The parental DNA unwinds and each strand serves as template for the synthesis of complementary strands.</em>
In the case of XNA, the two strands of parental XNA were found intact, meaning that the newly produced XNA consist of two newly synthesized strands. This thus means that the replication process is conservative.
Hence, unlike DNA replication that is semi conservative, XNA replication is conservative.
The answer would be A. the arrangement of DnA
If it was a double heterozygote, then aabb will be AaAaBbBb.
It will form 4 types of gametes since we have Aa, Bb. It will have aB, AB, ab, Ab.
An individual will form
only 2 type of gametes, Aa, Bb.
