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3 years ago

I have a math question it is... what is g - 3/7 = 2/7 ?

Mathematics

1 answer:

stira [4]3 years ago

6 0

g - 3/7 = 2/7 is an equation.

$\displaystyle\bf\\g-\frac{3}{7}=\frac{2}{7}\\ \\g=\frac{2}{7}+\frac{3}{7}=\frac{2+3}{7}=\frac{5}{7}\\\\\boxed{\bf g=\frac{5}{7}}$

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Chris has already baked 1 pie, and she can bake 1 pie with each additional cup of sugar she buys. How many additional cups of su

stealth61 [152]

Answer:
37 cups because one for each pie right? Or would it be 36 cups since she already baked one.

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3 years ago

For the graph y = 1 find the slope of a line that is perpendicular to it and the slope of a line parallel to it. Explain your an

svetlana [45]

<span>For the graph y = 1, the slope of a line that is perpendicular would be infinity because it lies vertically. The slope of the line parallel to it will have the same slope with y=1 which is zero because it lies flat or horizontally. Hope this answers the question. Have a nice day.</span>

8 0

3 years ago

Please answer the question and show work. thx

igomit [66]

The solution of given system of linear equation is:

x=3 and y=10

Step-by-step explanation:

Given equations are:

-8x+5y=26 Eqn 1

9x-3y=-3 Eqn 2

Multiplying equation 1 by 9

-72x+45y=234 Eqn 3

Multiplying Equation 2 by 8

72x-24y=-24 Eqn 4

Adding Eqn 3 and 4

$-72x+45y+72x-24y=234-24\\ 21y=210$

Dividing both sides by 21

$\frac{21y}{21}=\frac{210}{21}\\y=10$

Putting y=10 in equation 1

$-8x+5(10)=26\\-8x+50=26$

Subtracting 50 from both sides

$-8x+50-50=26-50\\-8x=-24$

Dividing both sides by -8

$\frac{-8x}{-8}=\frac{-24}{-8}\\x=3$

Hence the solution of given system of linear equation is:

x=3 and y=10

Keywords: Linear Equations, Variables

Learn more about linear equations at:

#learnwithBrainly

5 0

3 years ago

Louise calculated the height of a cylinder that has a volume of 486 pi cubic centimeters and a radius of 9 centimeters. Her work

Bumek [7]

Step-by-step explanation:

Louise calculated the height of a cylinder that has a volume of 486 pi cubic centimetres and a radius of 9 centimetres.

The formula for the volume of cylinder is :

V = B × h

B is area of base of cylinder

$B=\pi r^2$

i.e.

$V=\pi r^2 h$

Substituting given values,

$486\pi =\pi (9)^2 \times h$

$\pi$ will cancel out from both sides.

$486= (9)^2 \times h\\\\h=\dfrac{486}{81}\\\\h=6\ cm$

She forgets to cancel down $\pi$ from both sides. So, she get height as $6\pi\ cm$ . So, in the $\pi$ should have canceled, making the correct answer 6 cm.

3 0

4 years ago

Read 2 more answers

Please help me with his math question

mr_godi [17]

Answer: ∠A = 55° (acute)

∠B = 105° (obtuse)

∠C = 86° (acute)

∠D = 114° (obtuse)

<u>Step-by-step explanation:</u>

Use Law of Cosines: a² = b² + c² - 2bc · cosA for each of the angles.

Note that ∠B from each triangle will have to be added to solve for ∠B.

Similarly for ∠D.

For ΔDAB: a = 9.1, b = 7.3, d = 11

9.1² = 7.3² + 11² - 2(7.3)(11) · cosA

82.81 = 53.29 + 121 - 160.6 · cosA

-91.48 = -160.6 cosA

0.5696 = cos A

55° = A

b² = a² + c² - 2ac · cosB

7.3² = 9.1² + 11² - 2(9.1)(11) · cosB

53.29 = 82.81 + 121 - 200.2 · cosB

-150.52 = -200.2 cosB

0.7518 = cosB

41° = B

ΔDAB: ∠A + ∠B + ∠D = 180°

55° + 41° + ∠D = 180°

96° + ∠D = 180°

∠D = 84°

*****************************************************

For ΔBCD: b = 8.2, c = 9.1, d = 4.6

b² = c² + d² - 2cd · cosB

8.2² = 9.1² + 4.6² - 2(9.1)(4.6) · cosB

67.24 = 82.81 + 21.16 - 83.72 · cosB

-36.73 = -83.72 cosB

0.4387 = cosB

64° = B ∠B in ABCD = 41° + 64° = 105°

c² = b² + d² - 2bd · cosC

9.1² = 8.2² + 4.6² - 2(8.2)(4.6) · cosC

82.81 = 67.24 + 21.16 - 75.44 · cosC

-5.59 = -75.44 cosC

0.074 = cosC

86° = C

d² = b² + c² - 2bc · cosD

4.6² = 8.2² + 9.1² - 2(8.2)(9.1) · cosD

21.16 = 67.24 + 82.81 - 149.24 · cosD

-128.89 = -149.24 cosD

0.8636 = cosD

30° = D ∠D in ABCD = 84° + 30° = 114°

****************************************************************************

Acute angles are those that are less than 90° --> ∠A & ∠C

Obtuse angles are those that are greater than 90° --> ∠B & ∠D

6 0

4 years ago