Using productivity software ensures that the end product will look professional. Please select the best answer from the choices
1 answer:
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Answer:
Following are the code to this question:
import java.util.*;//import package for user input
public class Main//defining class main
{
public static boolean odd_number_digits(int n)//defining boolean method odd_number_digits
{
if(n>0 && n%2!=0)//defining if block that check value is positive and odd number
{
return true;//return value true
}
else//defining else block
{
return false;//return false value
}
}
public static void sum_odd_digits(int n)//defining a method sum_odd_digits
{
int sum=0,i;//defining integer variable
for(i=0;i<=n;i++)//defining for loop
{
if(i%2!=0)//defining if block for odd number
{
sum=sum+i;//add odd number
}
}
System.out.print(sum);//use print method to print sum value
}
public static void main(String[] args) //defining main method
{
Scanner ox=new Scanner(System.in);//creating Scanner object
int n= ox.nextInt();//defining integer variable for input value
System.out.print(odd_number_digits(n)+ "\n");//use print method to call method
System.out.println("Sum of odd numbers: ");//print message
sum_odd_digits(n);//calling method
}
}
Output:
please find the attachment.
Explanation:
In the above code, two methods "odd_number_digits and sum_odd_digits" are defined in which the first method return type is boolean because it will true or false value, and the second method returns the sum of odd numbers.
In the "odd_number_digits" method, an integer variable passes as an argument and inside the method, if block is used that check value is a positive and odd number then it will return a true value.
In the "sum_odd_digits" method, it accepts an integer parameter "n", and define integer variable "sum" inside the method, which uses the for loop, inside the loop if block is used that counts odd numbers and adds its in sum and print its value.
