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3 years ago

The length of a rectangle is 2.3 inches more than the width. Find the dimensions of the

Mathematics

2 answers:

SCORPION-xisa [38]3 years ago

7 0

Answer:

See image

Step-by-step explanation:

Let w=width

And let l=length

Perimeter is the distance all the way around the outside of the shape. Add up all the sides to find it.

gavmur [86]3 years ago

7 0

Step-by-step explanation:

let the width of the rectangle=x

the length=x+2.3

Since perimeter=28.6

We know that perimeter of a rectangle is given by

P=2(l+w)

28.6=2(x+2.3+x)

28.6=2(2x+2.3)

28.6=4x+4.6

28.6-4.6=4x

4x=24

x=24/4=6

Therefore width is 6inches and length is 8.3inches

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What is 2/3+3m/5=31/15? Please show your work! Thank You!

scZoUnD [109]

Answer:

m = $\frac{7}{3}$

Step-by-step explanation:

Given

$\frac{2}{3}$ + $\frac{3m}{5}$ = $\frac{31}{15}$

Multiply through by 15 to clear the fractions

15 is the lowest common multiple of 3, 5 and 15

10 + 9m = 31 ( subtract 10 from both sides )

9m = 21 ( divide both sides by 9 )

m = $\frac{21}{9}$ = $\frac{7}{3}$

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3 years ago

If anyone can answer please help meh

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

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4 years ago

What is the measurement in degrees and radians for the rotation of counter-clockwise 5/3

irga5000 [103]

I am assuming 5/3 refers to 5/3rds of a full revolution.
radians is easier for now so I'll do that first. on full revolution = 2π radians, but you have 1 and 2/3rds revolutions, so that is 2π+2π*(2/3)=10π/3 radian turn
to convert from radians to degrees multiply the radians by 180/π, so (10π/3)*(180/π) => 600degrees
Final answer:
5/3 turn is 600 degrees and 10π/3 radians
Hope I helped :)

5 0

4 years ago

3. Find cos(A). Show your work and reduce the ratio if necessary.

anygoal [31]

Answer:

cosA = $\frac{3}{5}$

Step-by-step explanation:

cosA = $\frac{adjacent}{hypotenuse}$ = $\frac{AB}{AC}$ = $\frac{30}{50}$ = $\frac{3}{5}$

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3 years ago

Suppose that the concentration (measured in gm^-3) of nitrogen in the soil along a transect in moist tundra yields data points t

kap26 [50]

Answer:

The average concentration of nitrogen in the soil along 0 ≤ x ≤ 10 is $y_{avg}=500.3 \:{\frac{g}{m^3} }$

Step-by-step explanation:

To find the average concentration between two points a and b along a transect, we measure the concentration at equal distances. Assume that f(x) is a continuous function on [a, b]. The average value of f on the interval [a, b] is

$f_{avg}=\frac{1}{b-a} \int\limits^b_a {f(x)} \, dx$

To find the average concentration of nitrogen we have to take the integral over the entire range and then dividing by the distance covered in the study.

$y_{avg}=\frac{1}{10-0}\int\limits^{10}_{0} {(673.8 - 34.7x)} \, dx \\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\y_{avg}=\frac{1}{10-0}\int _0^{10}673.8dx-\int _0^{10}34.7xdx\\\\y_{avg}=\frac{1}{10-0}(6738-1735)\\\\y_{avg}=\frac{5003}{10}=500.3$

7 0

3 years ago