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Vsevolod [243]
2 years ago
10

How to find the anwser to 4=(2+2x)-x

Mathematics
1 answer:
aleksandrvk [35]2 years ago
6 0
4 = (2+2x)-x
4 = (2+2(2))-2
4 = (2+4)-2
4 = 6-2
4 = 4 
Which makes x=2  

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A car drives 10 1/2 miles in 1/6 hour. what is its speed in miles per hour
EastWind [94]
(Credit to guy/girl above) 63 miles 10 1/2 x 6 is 63.
7 0
2 years ago
Graph the relation. Is the relation a function? Why or why not? {(–1, 1), (–2, 1), (–2, 2), (0, 2)} Yes; there is only one domai
Luden [163]

{(–1, 1), (–2, 1), (–2, 2), (0, 2)}

In a function, each input has an output

Each domain has a range. In a function, range can be repeated but domain cannot be repeated. Same domain cannot have two range values.

Here domain is {-1, -2, -2, 0}

Range is { 1, 1, 2, 2}

Domain -2 is repeating so this relation is not a function

Answer : No; a domain value has two range values.


7 0
3 years ago
Solve: The quantity 2 x minus 20 divided by 3 = 2x −5 −3 2 13
harina [27]
(2x-20)/3 = 2x start by multiplying both sides by 3
8 0
3 years ago
What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that t
Inga [223]

Answer:

f(2n)-f(n)=log2

b.lg(lg2+lgn)-lglgn

c. f(2n)/f(n)=2

d.2nlg2+nlgn

e.f(2n)/(n)=4

f.f(2n)/f(n)=8

g. f(2n)/f(n)=2

Step-by-step explanation:

What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]

from a

f(n)=logn

f(2n)=lg(2n)

f(2n)-f(n)=log2n-logn

lo(2*n)=lg2+lgn-lgn

f(2n)-f(n)=lg2+lgn-lgn

f(2n)-f(n)=log2

2.f(n)=lglgn

F(2n)=lglg2n

f(2n)-f(n)=lglg2n-lglgn

lg2n=lg2+lgn

lg(lg2+lgn)-lglgn

3.f(n)=100n

f(2n)=100(2n)

f(2n)/f(n)=200n/100n

f(2n)/f(n)=2

the time will double

4.f(n)=nlgn

f(2n)=2nlg2n

f(2n)-f(n)=2nlg2n-nlgn

f(2n)-f(n)=2n(lg2+lgn)-nlgn

2nLg2+2nlgn-nlgn

2nlg2+nlgn

5.we shall look for the ratio

f(n)=n^2

f(2n)=2n^2

f(2n)/(n)=2n^2/n^2

f(2n)/(n)=4n^2/n^2

f(2n)/(n)=4

the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare

6.n^3

f(n)=n^3

f(2n)=(2n)^3

f(2n)/f(n)=(2n)^3/n^3

f(2n)/f(n)=8

the ratio will be times 8 the initial

7.2n

f(n)=2n

f(2n)=2(2n)

f(2n)/f(n)=2(2n)/2n

f(2n)/f(n)=2

5 0
2 years ago
Haley has enlarged a 3-inch by 5-inch picture so that both the length and width are tripled. The area of the enlarged photo is h
77julia77 [94]

Answer:

9 times

Step-by-step explanation:

Area = length x breadth

area of picture not enlarged = 3 x 5 = 15in²

If length is tripled it becomes , 3 x 3 = 9in

If width is tripled, it becomes , 5 x 3 = 15in

Area of enlarged picture = 9in x 15in = 135in²

amount by which enlarged image is larger = 135in² /15in² = 9

5 0
2 years ago
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