Let's say you want to compute the probability
where
converges in distribution to
, and
follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing
such that its mean and variance are the same as those for
.
Example: If
is binomially distributed with
and
, then
has mean
and variance
. So you can approximate a probability in terms of
with a probability in terms of
:
where
follows the standard normal distribution.
Answer:
See explanation
Step-by-step explanation:
Chevy Malibu hybrid = 6.8
Ford mustang = 9.6
Nissan Pathfinder = 10.8
Toyota Corolla = 6.3
1. Chevy Malibu hybrid to Toyota Corolla = 6.8 to 6.3
= 6.8 : 6.3
= 6.8 / 6.3
2. Nissan Pathfinder to Ford mustang = 10.8 to 9.6
= 10.8 : 9.6
= 10.8 / 9.6
= 2.7 / 2.4
3. Toyota Corolla to Nissan Pathfinder = 6.3 to 10.8
= 6.3 : 10.8
= 6.3 / 10.8
4. Ford mustang to Chevy Malibu hybrid = 9.6 to 6.8
= 9.6 : 6.8
= 9.6 / 6.8
= 2.4 / 1.7
Answer:
Step-by-step explanation:
(x – 4)(x – 4) = 0.
So factor are x-4=0
X=4 (D) is the answer
Answer:
for the first question it would be A. 4+8+16+32 because infinite series are such as :
9,18,36,72,144,288
10,20,40,80,160,
so basically its multiplying *2
I cant do #2 without seeing the formula
100%-30%=70%
100%+30%=130%
to decrese by 30%, multiply by 70%
to increase by 30%, multiply by 130%
