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Lera25 [3.4K]
2 years ago
15

Find the height of the trapezoid. 7 m Area = 51 m2 10 m

Mathematics
1 answer:
andrew11 [14]2 years ago
3 0
The answer is 6

h = 2 A/a+b = 2 51/10+7 = 6
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HELP! PLEASE! I really need help with this question!
LekaFEV [45]

Answer:

They are at the same height at 1.13 seconds.

Step-by-step explanation:

Remark

The rockets are at the same height when  f(x) = g(x) [see below] are the same. So you can equate them.

Givens

f(x) = - 16x^2 + 74x + 9

g(x) = -16x^2 + 82x              I have changed this so you don't have 2 f(x)s

Solution

  • f(x) = g(x)
  • -16x^2 + 74x + 9 = -16x^2 + 82x                        Add:  16x^2 to both sides
  • -16x^2+16x^2+74x + 9 = -16x^2+16x^2 + 82x   Combine terms
  • 74x + 9 = 82x                                                     Subtract 74x from both sides
  • 74x - 74x + 9 = 82x - 74x                                  Combine
  • 9 = 8x                                                                 Divide by 8
  • 9/8 = 8x/8
  • x = 1 1/8                                                              Convert to decimal
  • x = 1.125
  • x = 1.13  [rounded]


6 0
3 years ago
Help me please i need help
scoundrel [369]

Answer:

3/11 = 6/22

Step-by-step explanation:

3*2=6.

so 11*2 = 22

4 0
3 years ago
Read 2 more answers
Find the product of 2.7 and 3.59.
Paha777 [63]

Answer:

9.693 hope this helps!!!

3 0
2 years ago
The SAT scores have an average of 1200 with a standard deviation of 60. A sample of 36 scores is selected. a) What is the probab
LiRa [457]

Answer:

a) 0.0082

b) 0.9987

c) 0.9192

d) 0.5000

e) 1

Step-by-step explanation:

The question is concerned with the mean of a sample.  

From the central limit theorem we have the formula:

z=\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }

a) z=\frac{1224-1200}{\frac{60}{\sqrt{36} } }=2.40

The area to the left of z=2.40 is 0.9918

The area to the right of z=2.40 is 1-0.9918=0.0082

\therefore P(\bar X\:>\:1224)=0.0082

b) z=\frac{1230-1200}{\frac{60}{\sqrt{36} } }=3.00

The area to the left of z=3.00 is 0.9987

\therefore P(\bar X\:

c) The z-value of 1200 is 0

The area to the left of 0 is 0.5

z=\frac{1214-1200}{\frac{60}{\sqrt{36} } }=1.40

The area to the left of z=1.40 is 0.9192

The probability that the sample mean is between 1200 and 1214 is

P(1200\:

d) From c) the probability that the sample mean will be greater than 1200 is 1-0.5000=0.5000

e) z=\frac{73.46-1200}{\frac{60}{\sqrt{36} } }=-112.65

The area to the left of z=-112.65 is 0.

The area to the right of z=-112.65 is 1-0=1

5 0
3 years ago
What is the length of DE?
Andrew [12]

Answer:

The length of DE is 5 because they are similar triangle .

7 0
2 years ago
Read 2 more answers
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