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IgorC [24]
4 years ago
14

Mark Went to the store and purchase nine pairs of socks and three packages of undershirts for $8.28 each he also purchase a pair

of pants for $32 he spent a total of $77.99 how much did he pay for each pair of socks write an equation using the variable S
Mathematics
1 answer:
agasfer [191]4 years ago
7 0

Answer:

He paid $2.35 for each pair of socks.

An equation using the variable S is

$77.99 = 9S + (3 × $8.28) + $32

Step-by-step explanation:

Let S be the cost of a pair of socks

From the question, Mark purchase nine pairs of socks, that is, the total cost of the pairs of socks is 9S

He purchase three packages of undershirts for $8.28 each; the total cost of the three packages of shirt will be 3 × $8.28 = $24.84

and he also purchase a pair of pants for $32

Since he spent a total of $77.99, we can write that

$77.99 = 9S + (3 × $8.28) + $32

Now, we can determine S, the cost of a pair of socks

$77.99 = 9S + (3 × $8.28) + $32

$77.99 = 9S + $24.84 + $32

$77.99 = 9S + $56.84

9S = $77.99 - $56.84

9S = $21.15

S = $21.15/9

S = $2.35

Hence, he paid $2.35 for each pair of socks.

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Please solve this question!!​
GaryK [48]

Answer:  (i) 1/221     (ii) 11/221      (iii) 95/663        (iv) 1/663

<u>Step-by-step explanation:</u>

(i) A deck of cards contains 4 Kings out of 52 total cards

1st draw: 4 Kings out of 52 total cards → 4/52 = 1/13

2nd draw: 3 remaining Kings out of 51 total remaining cards  →  3/51 = 1/17

  <u>1st Draw </u>                   <u>2nd Draw </u>                  <u>Outcome</u>         <u>Probability</u>

 King: P(K) = 1/13        King: P(K₂/K₁) = 1/17     King, King       (1/13) x (1/17) = 1/221

*************************************************************************************************

(ii) A deck of cards contains 4 Jacks, 4 Queens, & 4 Kings out of 52 total cards

1st draw: 12 Face cards out of 52 total cards → 12/52 = 3/13

2nd draw: 11 remaining Face cards out of 51 total remaining cards  →  11/51

<u>1st Draw </u>                 <u>2nd Draw </u>                  <u>Outcome</u>       <u>Probability</u>

 Face: P(F) = 3/13    Face: P(F₂/F₁) = 11/51   Face,Face     (3/13) x (11/51) = 11/221

*************************************************************************************************

(iiI) A deck of cards contains 26 black cards out of 52 total cards but there are 2 black Jacks, 2 black Queens, and 2 black Kings.

1st draw: 20 Black (not Face) cards out of 52 total cards → 20/52 = 5/13

2nd draw: 19 remaining Black (not Face) cards out of 51 total remaining cards  →  19/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                       <u>Outcome</u>   <u>Probability</u>

Black: P(B~) = 5/13   Black: P(B~₂/B~₁) = 19/51    B~,B~    (5/13) x (19/51) = 95/663

*************************************************************************************************

(ii) A deck of cards contains 4 Aces out of 52 total cards

1st draw: 4 Aces out of 52 total cards → 4/52 = 1/13

2nd draw: 1 Queen of Hearts out of 51 total remaining cards  →  1/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                   <u>Outcome</u>         <u>Probability</u>

 Ace: P(A) = 1/13      Qh: P(Qh₂/A₁) = 1/51   Ace,Queen(h)   (1/13) x (1/51) = 1/663

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Answer:C would be the correct answer

Step-by-step explanation:

3 0
3 years ago
(B-c) / (2b-a). A=10, b= -4, c=63
Snowcat [4.5K]
(-4-63)\(2x-4-10)-8-10
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Answer:

64 textbooks

Step-by-step explanation:

the first two teachers had 21 students each that's 21+21=42

the other teacher had 22 students so apparently all the textbooks handed to the students are,21+21+22=64

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daser333 [38]

Answer:

20.00

Explanation:

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