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3 years ago

If x=15 and y= -5 then what is the value of x/y?

Mathematics

2 answers:

ludmilkaskok [199]3 years ago

7 0

The answer would be -3

OLEGan [10]3 years ago

4 0

Just divide as usual.

15/5 = 3

So, if you have a negative then your answer is -3.

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Domain: Ranges: Zeros: Discontinuities: Asymptotes:

trapecia [35]

Domain: The set of possible values of x

Range: The set of possible values of y

Zeros: The x-intercepts (what value of x is on the x-axis)

Discontinuities: Where the graph stops (and restarts somewhere else)

Asymptotes: The graph cannot cross this line (vertical, horizontal, oblique)

4 0

3 years ago

The are of a shaded region is 118 ft squared. Which equation can be- used to find the value of X, in feet?

Triss [41]

Answer:

$x^2+ 18x -130=0$

Step-by-step explanation:

Given

See attachment for diagram

Required

The equation to find x

First, calculate the area of the big rectangle using:

$Area = Length * Width$

So:

$A_1 = (x + 6) * (3x - 2)$

The smaller rectangle

$A_2 = (x - 1) * (2x)$

The difference between this areas give the area of the shaded region.

So:

$A_1 - A_1 = 118$

$(x+6)*(3x-2) - (x-1)*2x = 118$

Open brackets

$3x^2 - 2x + 18x -12 -2x^2 +2x = 118$

Collect like terms

$3x^2 -2x^2- 2x +2x+ 18x -12 - 118=0$

$x^2+ 18x -130=0$

The above equation can be used to solve for x

4 0

3 years ago

Answer dis please- Thanks

hodyreva [135]

Answer:

Since we know that ABCD ~ EFGH, we have the ratios:

EF/AB = GH/CD

=> 0.4/1.2 = x/1.8

=> x = (1.8 . 0.4)/1.2 = 0.6

So x = 0.6

8 0

3 years ago

Please help me this is due tonight

goldenfox [79]

Answer:

B = (2, -5)

Step-by-step explanation:

The problem requirements mean ...

B - A = (2/3)(C - A)

B = A + (2/3)C - A

B = (1/3)A + (2/3)C = (A +2C)/3

B = ((-6, 1) +2(6, -8))/3 = (-6+12, 1-16)/3 = (6, -15)/3

B = (2, -5)

4 0

3 years ago

Find the limit , picture provided

V125BC [204]

Answer:

d. does not exist

Step-by-step explanation:

The given limits are;

$\lim_{x \to 4} f(x) =5$ , $\lim_{x \to 4} g(x) =0$ and $\lim_{x \to 4} h(x) =-2$

We want to find

$\lim_{x \to 4} \frac{f}{g}(x)= \lim_{x \to 4} \frac{f(x)}{g(x)}$

By the properties of limits, we have;

$\lim_{x \to 4} \frac{f}{g}(x)= \frac{\lim_{x \to 4} f(x)}{\lim_{x \to 4} g(x)}$

This gives us;

$\lim_{x \to 4} \frac{f}{g}(x)= \frac{5}{0}$

Division by zero is not possible. Therefore the limit does not exist.

7 0

3 years ago