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steposvetlana [31]
3 years ago
10

draw the lewis structure for co with an arrow representing the dipole moment. refer to figure 10.10 to estimate the percent ioni

c character of the co bond.
Chemistry
1 answer:
Alona [7]3 years ago
5 0
Problem 57EDraw the Lewis structure for CO with an arrow representing the dipole moment. UseFigure 9.10 to estimate the percent ionic character of the CO bond. Step by step solutionStep 1 of 2Lewis structure of CO:Carbon has four valence electrons and oxygen has six valence electrons. If only one bond wereto be formed between carbon and oxygen atoms, carbon would have five electrons and oxygenwould have seven electrons.The single bond between these two atoms is not sufficient to lead to an octet on each atom . Tocomplete the octet of each atom in CO, we must employ a triple bond .A triple bond is formed bythe six electrons sharing between these two atoms and it is shown as follows.\nThe Lewis structure of CO with an arrow representing the dipole moment.The arrow towards anoxygen atom it represents is a highly electronegative atom.
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Magnesium burns with a very bright light. When the flame goes out, a White powder is left behind. what is the word equation for
melisa1 [442]
When magnesium is burned, it reacts with oxygen in air not with the fire. The fire is the energy needed for the reaction to happen. Magnesium reacts with oxygen forming magnesium oxide. The light emitted from the reaction is because the reaction produced a lot of heat.
6 0
3 years ago
a 3.50L sample of neon gas has a pressure of .950atm at 20c what would the volume be if the pressure increased to 1.50atm and th
ehidna [41]

Answer:

V_2=2.22L

Explanation:

Hello,

In this case, we use the Boyle's law which allows us to understand the volume-pressure behavior as an inversely proportional relationship:

P_1V_1=P_2V_2

Thus, solving for the final volume, once the pressure changes, we obtain:

V_2=\frac{P_1V_1}{P_2}=\frac{3.50L*0.950atm}{1.50atm}  \\\\V_2=2.22L

Best regards.

8 0
4 years ago
To aid in the prevention of tooth decay, it is recommended that drinking water contains 0.900 ppm fluoride (F-). A) How many g o
Romashka-Z-Leto [24]

Answer:

a) <u>1.740 g</u> of F- must be added to a cylindrical water reservoir

b) Grams of sodium fluoride, NaF, that contain this much fluoride:

3.84 g

Explanation:

Step 1. calculate the volume of the tank:

Volume of cylinder =

\pi  r^{2}h ,

Here r = radius of the cylinder = d/2

h = depth = 21.80m

r=\frac{d}{2}

=\frac{3.36x10^{2}}{2}

= 168 m

Volume =

=\frac{22\times 168^{2}\times 21.80}{7}

=1.93\times 10^{6} m^{3}

2.Convert ppm to g/m3 and Solve for mass of F-

1ppm = 1g/m^{3}

0.9ppm = 0.9g/m^{3}

Because both ppm and g/m3 are same quantity .

g/m^{3} =\frac{mass\ of\ F-(g)}{Volume\ m^{3}}\times 10^{6}

0.9 =\frac{mass\ of\ F-}{1.93\times 10^{6} m^{3}}\times 10^{6}

mass\ of\ F- =1.740g

mass of F- required = 1.740 g

3. Apply <u>mole concept </u>to calculate grams of sodium fluoride produced

mass of 1 mole of F2 = 38 g

mass of 1 mole of NaF = 42 g

(from periodic table calculate molar mass)

2Na+F_{2}\rightarrow 2NaF

Here 1 mole of F2 produce = 2 mole of NaF

So,

38 g  of F2 produce = 2 x 42 g of NaF

38 g of F2 produce = 84 g of NaF

1 g of F2 produce = 84/38 g of NaF

1.74 g F2 produce =

\frac {84}{38}\times 1.74

1.74 g F2 produce = 3.84 g of NaF

3.84 g of NaF is produced

3 0
3 years ago
If you have an aqueous solution that contains 1.5 moles of HCl, how many moles of ions are in the solution?
Citrus2011 [14]
There will be three moles of ions.
Because in an aqueous solution, HCl will break apart into  <span>H<span>+ and Cl- ions. 
</span></span>HCl -> <span>H+</span><span> + </span><span>C<span>l<span>−
</span></span></span>1.5 HCl -> 1.5 H+ + 1.5 Cl−<span>
So the aqueous solution will have 1.5 moles of hydrated hydrogen ions and 1.5 moles of hydrated chloride ions. So, a total of 3 moles of ions are present in the aqueous solution of 1.5 moles of HCl. </span>
6 0
3 years ago
Can anyone solve this?
Sonja [21]

Answer:

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P:6 O:15

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C:5 O:10

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C:18 H:36 O:18

4C6H12

C:24 H:48

3Mg3(PO4)2

Mg:9 P:2 O: 8

4(NH4)2S

N:8 H:32 S:4

4 0
3 years ago
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