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Rainbow [258]
3 years ago
5

Jack wants to share his candy with friends. Right now he has 4 1/3 pieces of chocolate. How many friends can he give 1/2 a candy

bar to?
Mathematics
1 answer:
cricket20 [7]3 years ago
3 0

Answer:

8 Friends

Step-by-step explanation:

First convert 4 1/3 to a mixed fraction

4 1/3 --> 13/3

Then divide by 1/2 to find how many friends per 1/2 candy bar with 13/3 candy bars

(13/3)/(1/2)

=(13*2)/(3*1)

=26/3

8.66667

Since you can't have 0.66667 of a person you get 8 friends to give candy to

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Which point is on the line, y=4x+2?
frosja888 [35]
I did the math and (6,26) is the correct answer.
3 0
3 years ago
Solve the system using elimination.
expeople1 [14]

Answer:

(- 9, - 9)

Step-by-step explanation:

Given the 2 equations

3x - 4y = 9 → (1)

- 3x + 2y = 9 → (2)

Adding (1) and (2) will eliminate the term in x

(1) + (2) term by term

(3x - 3x) + (- 4y + 2y) = (9 + 9)

0 - 2y = 18

- 2y = 18 ( divide both sides by - 2 )

y = - 9

Substitute y = - 9 into (1) or (2) and evaluate for x

(1) → 3x + 36 = 9 ( subtract 36 from both sides )

3x = - 27 ( divide both sides by 3 )

x = - 9

Solution is (- 9, - 9)

3 0
4 years ago
Cari owns a horse farm and a horse trailer than can transport up to 8000 pounds of livestock and tack. She travels with 5 horses
tatuchka [14]
In order to find out the answer for this, let us try to analyze the question. Since it is given that 6240 pounds is the total weight of her 5 horses and t represents the weight of each tack per horse, the inequality that could be used to determine the weight of tack Cari can allow for each horse would be this: <span>6240+5t≤8000
6240+5t indicates the total weight, and that this weight does not exceed 8000. Hope this answer helps.</span>
7 0
3 years ago
If m/CHF = 106°, then what is m/FHD?
densk [106]

Answer:

74 degrees

Step-by-step explanation:

The two angles in question form a straight line (180 degrees)

   180 = CHF + FHD

  180 = 106 + FHD

180 - 106 = FHD

   FHD = 74 degrees

5 0
2 years ago
The box plot is based on the?<br> mean<br> median<br> mode<br> range
Westkost [7]

PLEASE GIVE BRAINLIST

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hope this helped

3 0
3 years ago
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