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3 years ago

PLEASE help asap if u know the answer!!!! quadratic functions:vertex form thank you!!!

Mathematics

1 answer:

SOVA2 [1]3 years ago

6 0

Answer:

The answer to your question is: third option, it's a parabola

Step-by-step explanation:

f(x) = (x + 4)²

f(x) = x² + 4

f(x) = (x - 4)² I think this is the right answer, because when get the vertex, the signs are changed, if the -4 is negative, it means that the graph must be located in +4.

f(x) = x² - 4

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Answer:

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Step-by-step explanation:

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3 years ago

Determine the quadratic function f whose graph is given. The vertex is (1,-3) and y-intercept is -2

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Answer:

Vertex form: $f(x)=(x-1)^2-3$

Standard form: $f(x)=x^2-2x-2$

Step-by-step explanation:

A quadratic function in vertex form is $f(x)=a(x-h)^2+k$ where $(h,k)$ is the vertex.

We are given $h=1,k=-3$ .

Let's plug that in:

$f(x)=a(x-1)^2-3$ .

Now let's find $a$ .

We will use the $y$ -intercept $(0,-2)$ to find $a$ .

$f(0)=a(0-1)^2-3$

$-2=a(0-1)^2-3$

$-2=a(-1)^2-3$

$-2=a(1)-3$

$-2=a-3$

$1=a$

So the function in vertex form is:

$f(x)=(x-1)^2-3$ .

In standard form, we will have to multiply and combine any like terms.

Let's do that:

$f(x)=(x-1)(x-1)-3$

$f(x)=x^2-x-x+1-3$

$f(x)=x^2-2x-2$

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4 years ago

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Answer:

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Step-by-step explanation:

4/7 ÷7/2

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