Answer:
- see the attachment
- (x, y) = (1, 1)
Step-by-step explanation:
1. Since you have y > ..., the boundary line is dashed and the shading is above it (for y-values greater than the values on the line). The boundary line is ...
y = 2x+3
which has a y-intercept of 3 and a slope (rise/run) of 2. A graph is attached.
__
2. You can add the two equations to eliminate y:
(3x +y) +(x -y) = (4) +(0)
4x = 4
x = 1
1 - y = 0 . . . . substitute into the the second equation
1 = y . . . . . . . add y
The solution is (x, y) = (1, 1).
Answer:
Step-by-step explanation:
y = 3.2x+5
This equation represents a straight line where 3.2 is the slope of the line and 5 is the intercept of the line on the y-axis (basically where the line touches the y-axis)
So,because this is a line you only need two points to draw it.
One point you already know it's y =5.
To find another point that lies on the line just substitute a convenient number for x.For example say if x= 1/3.2
y = 3.2*( 1/3.2) +5
Therefore:
y = 1+5 =6
So,the other point on the line is (1/3.2 , 6)
Now find the points y = 5 and (1/3.2 , 6) on the xy plane and draw the line passing through them.
²⁰¹²C₂₀₁₁ = (2012)! / [(2011)! (2012-2011)!]
²⁰¹²C₂₀₁₁ = (2012)! / [(2011)! (1)!]
Simplify 2012! / (2011)! = 2012
²⁰¹²C₂₀₁₁ = (2012)! / (1)! = 2012
Answer:
x = -1 y = - 13/6
Step-by-step explanation: