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tester [92]
3 years ago
14

Craig has a rectangle wooden deck that measures 799 inches by 245 inches that he wants to put a string of lights around. What le

ngth of lights should he buy?
Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0

Answer:

He should buy lights that are 2088 inches long

Step-by-step explanation:

Craig has a rectangle wooden deck that measures 799 inches by 245 inches.

Let us say the length, L, is 799 inches and the breadth, B, is 245 inches.

He wants to put a string of lights around the deck.

This means that he needs to buy the length of lights that would be equal to the perimeter of the rectangular deck.

The perimeter of a rectangle is given as:

P = 2(L + B)

Hence, the length of lights he should buy is:

P = 2(799 + 245) = 2(1044)

P = 2088 inches

He should buy lights that are 2088 inches long.

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3 years ago
A triangular paddock has a road AB forming its
leva [86]
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4 0
3 years ago
Help will mark as brainless thanks
Rashid [163]

Answer:

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7 0
3 years ago
Needs answers <br> Will mark brainliest
Elden [556K]

QUESTION 1:

Required angles are: m<2=75°, m<3=75°, m<4= 105°, m<5= 105°, m<6=75°, m<7=75°, m<8=105°

QUESTION 2:

Required angles are: m<1=100° m<2=80°, m<4= 100°, m<5= 100°, m<6=80°, m<7=80°, m<8=100°

Step-by-step explanation:

Question 1:

if m<1 =105°

We need to find the remaining angles.

The corresponding angles of a traversal are same. so the corresponding angle of <1 is angle 5 So, m<5 = 105°

The vertical angles are also equal. so, vertical angle of <1 is <4. So, m<4 = 105°

Vertical angles of m<5 is m<8 so, m<8=105°

m<1 and m<2 are supplementary angles of each other so their sum will be equal to 180°

So, m<1+m<2=180

105+m<2=180

m<2=75°

Same goes for m<3 and m<4 so, m<3 = 75°

m<5 and m<6 so, m<6 = 75°

m<7 and m<8 so, m<7= 75°

So, required angles are: m<2=75°, m<3=75°, m<4= 105°, m<5= 105°, m<6=75°, m<7=75°, m<8=105°

Question No 2

if m<3=80°

We need to find the remaining angles.

The corresponding angles of a traversal are same. so the corresponding angle of <3 is angle 7 So, m<7 = 80°

The vertical angles are also equal. so, vertical angle of <3 is <2. So, m<2 = 80°

The Vertical angle of <7 is <6 so, m<6= 80°.

m<1 and m<2 are supplementary angles of each other so their sum will be equal to 180°

So, m<1+m<2=180

m<1+80=180

m<1=100°

Same goes for m<3 and m<4 so, m<4 = 100°

m<5 and m<6 so, m<5 = 100°

m<7 and m<8 so, m<8= 100°

So, required angles are: m<1=100° m<2=80°, m<4= 100°, m<5= 100°, m<6=80°, m<7=80°, m<8=100°

Keywords: Traversal of parallel lines

Learn more about traversal of parallel lines at:

  • brainly.com/question/1598227
  • brainly.com/question/3227215
  • brainly.com/question/10483199

#learnwithBrainly

3 0
4 years ago
find a model for simple harmonic motion if the position at t = 0 is 6, the amplitude is 6 centimeters, and the period is 4 secon
Y_Kistochka [10]

Answer:

y = 6cos(π/2)t

Step-by-step explanation:

Given in the question that,

in a simple harmonic motion in which

at t=0 the amplitude is 6 cm, so the simple harmonic motion will be in cosine form. As in case of sine function, the value of function at t=0 is 0.  

And,

the period is given as 4 sec

We know that model equation of simple harmonic motion is

<h3>y = a. cosb(t + c) + d</h3>

here,

a is amplitude

c is Horizontal shift or phase shift

d is Vertical shift

<h3>Step1</h3><h3>Find b</h3>

Period = 2 π / b

4 = 2π / b

b = 2π/4

b = 1π/2

<h3>Step2</h3><h3>Find shifts</h3>

Horizontal and vertical shifts are 0.

So, c = 0 and d = 0

<h3>Step3</h3><h3>Plug those values in the above in the equation</h3>

y = 6cos π/2 (t + 0) + 0

y = 6cos(π/2)t

4 0
4 years ago
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