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3 years ago

Rafael takes home $4200 per month. What is the maximum amount he can

Mathematics

1 answer:

galben [10]3 years ago

6 0

Answer:

A bad debt ratio of more than 10% is considered high and often is a sign that you are in danger of credit overload. So, I'd $420 is the maximum amount he can spend on credit card payments and loan each month.

Step-by-step explanation:

Let's clear this with an example:

Rafael makes $4,200 a month and let's say he spends $550 on credit card payments and $450 on an loans.

Then, the ratio calculation would be $1000 / $4,200 = 0.24

Multiply that by 100 for a debt-income-ratio of 24%.

In this example, Rafael spends almost a quarter of his income on debt which is considered bad debt in economics.

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Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar

oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 18 means that $N = 18$

9 are carrying nuclear weapons, which means that $k = 9$

9 are destroyed, which means that $n = 9$

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021$

$P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687$

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

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3 years ago

Rewrite in simplest terms: -0.2t - 5 (-8t + 5)

SVETLANKA909090 [29]

Answer: 40.2t - 25

Step-by-step explanation:

-0.2t - 5 (-8t + 5)

-0.2t + 40t -25

39.8t - 25

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3 years ago

Is this a true statement? 0.3711 > 0.3801

disa [49]

NO. It's FALSE.

$0.\ 3\ 7\ 1\ 1\\||\ ||\wedge\\0.\ 3\ 8$

therefore 0.3801 > 0.3711

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3 years ago

What is 2 5/12 - 1 7/12 =

castortr0y [4]

Answer:

Divide: 7/12 : 3/10 = 7/12 · 10/3= 7 · 10 /12 · 3 = 70/36 = 35/18

To divide one fraction by another, invert (turn upside-down) the second fraction, then multiply.

Hope this helps:)sorry if it doesnt

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3 years ago

How many times can 10 go into 111? lol i need help

ikadub [295]

Answer:

11.1 times

Step-by-step explanation:

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3 years ago

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