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Gwar [14]
3 years ago
6

Rafael takes home $4200 per month. What is the maximum amount he can

Mathematics
1 answer:
galben [10]3 years ago
6 0

Answer:

A bad debt ratio of more than 10% is considered high and often is a sign that you are in danger of credit overload. So, I'd $420 is the maximum amount he can spend on credit card payments and loan each month.

Step-by-step explanation:

Let's clear this with an example:

Rafael makes $4,200 a month and let's say he spends $550 on credit card payments and $450 on an loans.

Then, the ratio calculation would be $1000 / $4,200 = 0.24

Multiply that by 100 for a debt-income-ratio of 24%.

In this example, Rafael spends almost a quarter of his income on debt which is considered bad debt in economics.

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3) A woman buys 3 dezen eggs. Later she discovers that x of them are broken. How many mang eggs are not broken 3 ) A woman buys
Fofino [41]

Answer:

<h2><u><em>36 - x</em></u></h2>

Step-by-step explanation:

A woman buys 3 dezen eggs. Later she discovers that x of them are broken. How many mang eggs are not broken

3 = 3

Dozen = 12

x = broken eggs

3 * 12 - x =

36 - x

5 0
2 years ago
The coordinate plane below represents a city. Points A through F are schools in the city. graph of coordinate plane. Point A is
Ray Of Light [21]
Part A;
There are many system of inequalities that can be created such that only contain points A and E in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, -3) and (3, 1) but is not satisfied by (-3, -4), (-4, 2), (2, 4) and (-2, 3) can serve.

An example of such system of equation is
y ≤ x
y ≥ -2x
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the line y = -2x and to the right of the line y = x is shaded.



Part B:
It can be verified that points A and E are solutions to the system of inequalities above by substituting the coordinates of points A and E into the system of equations and see whether they are true.

Substituting A(2, -3) into the system we have:
-3 ≤ 2
-3 ≥ -2(2) ⇒ -3 ≥ -4
as can be seen the two inequalities above are true, hence point A is a solution to the set of inequalities.

Also, substituting E(3, 1) into the system we have:
1 ≤ 3
1 ≥ -2(3) ⇒ 1 ≥ -6
as can be seen the two inequalities above are true, hence point E is a solution to the set of inequalities.



Part C:
Given that William can only attend a school in her designated zone and that William's zone is defined by y < −x - 1.

To identify the schools that William is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining William's zone.

For point A(2, -3): -3 < -(2) - 1 ⇒ -3 < -2 - 1 ⇒ -3 < -3 which is false

For point B(-3, -4): -4 < -(-3) - 1 ⇒ -4 < 3 - 1 ⇒ -4 < 2 which is true

For point C(-4, 2): 2 < -(-4) - 1 ⇒ 2 < 4 - 1 ⇒ 2 < 3 which is true

For point D(2, 4): 4 < -(2) - 1 ⇒ 4 < -2 - 1 ⇒ 4 < -3 which is false

For point E(3, 1): 1 < -(3) - 1 ⇒ 1 < -3 - 1 ⇒ 1 < -4 which is false

For point F(-2, 3): 3 < -(-2) - 1 ⇒ 3 < 2 - 1 ⇒ 3 < 1 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point B and C.
4 0
3 years ago
Anyone want to help me out on this question?
kvasek [131]
Answer:

i think it’s 2/7
5 0
3 years ago
Test the claim below about the mean of the differences for a population of paired data at the level of significance α Assume the
Evgen [1.6K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  correct option is F

t =  1.17

t_ {\alpha , df} =t_ {0.10 , 8} = 1.86

Since the test statistics<u> is outside </u>the rejection region , <u>we fail to reject </u>the null hypothesis ,There<u> is no</u>  statistically significant evidence to reject the claim

Step-by-step explanation:

From the question we are told that

    The  claim is  \mu =  0

Hence  

      The  null hypothesis is  H_o  :  \mu = 0

       The  alternative is  H_a  :  \mu  \ne  0

Generally the test statistics is mathematically represented as  

                 t =  \frac{\= d - \mu_d }{ \frac{s_d}{ \sqrt{n} } }

=>              t =  \frac{3.5 -0 }{ \frac{8.94}{ \sqrt{9} } }

=>              t =  1.17

Generally the degree of freedom is mathematically represented as

      df  =  n- 1

      df  =  9 -  1

      df  =  8

From the student t-distribution table  the critical value of  \alpha at a degree of freedom of  8 is  

          t_ {\alpha , df} =t_ {0.10 , 8} = 1.86

Since the t_ {\alpha , df} is  outside the rejection region , we fail to reject the null hypothesis ,There is no sufficient evidence to reject the claim

4 0
3 years ago
IM CONFUSED. WILL GIVE BRANLIEST What is the value of x?
Katen [24]

Answer:

i'd say it's x=6

Step-by-step explanation:

........

5 0
3 years ago
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