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3 years ago

Rafael takes home $4200 per month. What is the maximum amount he can

Mathematics

1 answer:

galben [10]3 years ago

6 0

Answer:

A bad debt ratio of more than 10% is considered high and often is a sign that you are in danger of credit overload. So, I'd $420 is the maximum amount he can spend on credit card payments and loan each month.

Step-by-step explanation:

Let's clear this with an example:

Rafael makes $4,200 a month and let's say he spends $550 on credit card payments and $450 on an loans.

Then, the ratio calculation would be $1000 / $4,200 = 0.24

Multiply that by 100 for a debt-income-ratio of 24%.

In this example, Rafael spends almost a quarter of his income on debt which is considered bad debt in economics.

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What is the length of BC¯¯¯¯¯ ? Enter your answer in the box. units Triangle A B C with horizontal side B C. Vertex A lies above

OlgaM077 [116]

Answer: The length of BC is 22 units.

Explanation:

It is given that the Triangle ABC with horizontal side BC. Vertex A lies above side BC. Angle B and angle C are marked congruent. The length of side AC is labeled as 2x-24. The length of side AB is labeled as x-2. The length of side B C is labeled as x.

If two angles of a triangle are same it means the triangle is an isosceles triangle.

Since the angle B and C are congruent therefore the lines AB and AC are same.

$2x-24=x-2$

$2x-x=-2+24$

$x=22$

Since the side BC=x therefore the measure of BC is 22 units.

7 0

3 years ago

Determine the length of the arc that subtends an angle of 2.8 radians at the centre of a circle with a radius 12cm.

Svetach [21]

Answer:

B. 33.6 cm

Step-by-step explanation:

To find determine the length of an arc that subtends an angle of 2.8 radians at the centre of a circle with radius 12 cm, we will follow the steps below;

First write down the formula for calculating length of an arc

If the angle is measured in degree, then the formula for calculating the length of an arc is :

length of an arc = Ф/360 × 2πr

but if the angle is measured in radians, then the formula for calculating length of an arc will be:

length of an arc = r Ф

where r is the radius and Ф is the central angle in radians

In the case of the question given to us, the angle is given in radians, so we will use the second formula

angle Ф = 2.8

radius = 12 cm

length of an arc = r Ф

=12 × 2.8

=33.6

Length of the arc = 33.6 cm

6 0

2 years ago

Guys this is a real problem!!! Will mark brainliest!!

Igoryamba

311(1.50)+.50x=385.50

would be your equation

4 0

3 years ago

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What is 2x+4<br> dhfbwaehaskjbdjk.sabhdsahdiasebfsdafvasdgdsf

Mrac [35]

Answer: look at the picture

Step-by-step explanation: Hope this help :D

7 0

3 years ago

Suppose that 50% of all young adults prefer McDonald's to Burger King when asked to state a preference. A group of 12 young adul

ddd [48]

Answer:

a) 0.194 = 19.4% probability that more than 7 preferred McDonald's

b) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

c) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they prefer McDonalds, or they prefer burger king. The probability of an adult prefering McDonalds is independent from other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of all young adults prefer McDonald's to Burger King when asked to state a preference.

This means that $p = 0.5$

12 young adults were randomly selected

This means that $n = 12$

(a) What is the probability that more than 7 preferred McDonald's?

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.121$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.054$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.016$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.003$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.000$

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.121 + 0.054 + 0.016 + 0.003 + 0.000 = 0.194$

0.194 = 19.4% probability that more than 7 preferred McDonald's

(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.054$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.121$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.193$

$P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.226$

$P(X = 7) = C_{12,7}.(0.5)^{7}.(0.5)^{5} = 0.193$

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.054 + 0.121 + 0.193 + 0.226 + 0.193 = 0.787$

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?

Since $p = 1-p = 0.5$ , this is the same as b) above.

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

7 0

2 years ago