Answer:
length of an arc = 1unit
Step-by-step explanation:
given that the circumference of a circle = 6
central angle = 60
length of the arc =?
recall that the circumference of a circle = 2πr
6 = 2πr
r = 6/2π
now to calculate the length of an arc
recall,
length of an arc = 2πr(Ф/360)
length of an arc = 2π(6/2π) × 60/360
length of an arc = 6 × 60/360
length of an arc = 360/360
length of an arc = 1unit
therefore the length of the arc whose circumference is 6 and arc angle is 60° is evaluated to be 1unit
Answer:
a) x = -1.5
b) x = 1
Step-by-step explanation:
For problem a, you can start by subtracting 3x from both sides to gather all the like terms together:
7x + 5 = 3x - 1
-3x -3x
4x + 5 = -1
Next, to get the coefficients on one side, you subtract 5 from both sides:
4x + 5 = -1
-5 -5
4x = -6
Now, you divide by 4 on both sides to isolate x:
x = -6/4 = -1.5 --- > x = -1.5
For problem b, you start by subtracting 3x from both sides(kinda like problem a):
5x + 12 = 3x + 14
-3x -3x
2x + 12 = 14
Next, you can subtract 12 from both sides, isolating the "x term".
2x + 12 = 14
-12 -12
2x = 2
Lastly, you can divide by 2 to get x:
x = 1
Answer:
1.) No ;
2.) - 0.931
3.) 0.1785
Step-by-step explanation:
Given :
μ = 84.3 ; xbar = 81.9 ; s = 17.3
H0 : μ = 84.3
H1 : μ < 84.3
The test statistic :
(xbar - μ) ÷ (s/√(n))
(81.9 - 84.3) / (17.3/√45)
-2.4 / 2.5789317
= - 0.9306
= - 0.931
Using the test statistic, we could obtain the Pvalue : df = n - 1 ; df = 45 - 1 = 44
Using the Pvalue calculator :
Pvalue(-0.9306, 44) = 0.1785
Using α = 0.05
The Pvalue > α
Then we fail to reject H0; and conclude that there is no significant evidence to support the claim that the mean waiting time is less than 84.3
<span>2y/2=5x+1/2
y=5x/2+1/2
no it's not a direct variation because of 1/2</span>
