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AnnZ [28]
2 years ago
13

You participate in a dance-a-thon fundraiser. After your parents pledge $15.50 and your neighbor pledges $8.75, you have $66.55.

Write an equation to find how much money you had before your parents and neighbor pledged.
Mathematics
1 answer:
Nana76 [90]2 years ago
3 0

Answer:

15.50p+8.75n=66.55

Step-by-step explanation:

p=parents

n = neighbors

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In the diagram, BC is a radius of C. Determine whether AB is tangent to C. Explain your reasoning.
Whitepunk [10]

Answer:

No, AB is not tangent to C.

If it were tangent, it would form a right angle with the radius, and we could use Pythagorean's Theorem.

3²+6²=7²

9+36=49

45=49  Since this is false, it's not a right angle, and AB is not tangent.

Step-by-step explanation:

No, AB is not tangent to C.

If it were tangent, it would form a right angle with the radius, and we could use Pythagorean's Theorem.

3²+6²=7²

9+36=49

45=49  Since this is false, it's not a right angle, and AB is not tangent.

6 0
2 years ago
PLEASE HELPPPPP! Thank you!
kari74 [83]
Its mirrored i think

7 0
3 years ago
What is the range of the function y=-x² +1?<br> A) y≤ -1<br> B) y²-1<br> C) y≤ 1<br> D) y≥ 1
MakcuM [25]

Answer:

Option (C)

Step-by-step explanation:

The minimum value of x² is 0, and the maximum value is unbounded, so therefore, the maximum value of -x² is 0, and the minimum value is unbounded.

So, this means that adding 1 to this, the range matches with option C.

8 0
1 year ago
An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con
natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

L = 3w --- (1)volume = l \times w \times h \\ \\ 88 =  (3w)   \times w  \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\

The construction cost now is:

C = 4(l \times w) + 2 ( w  \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w  \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}

Now, to determine the minimum cost:

\dfrac{dC}{dw}= 0  \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}

w = \dfrac{88}{3(3)}^{1/3} \ feet

Now;

length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet

height = ( 88})^{1/3} (3)^{1/3} \ feet

6 0
2 years ago
What is the solution to the equation? (-9x+5)^1/2=(3+4x)1/2
Phoenix [80]
<span>x in (-oo:+oo)

((5-9*x)^1)/2 = ((4*x+3)^1)/2 // - ((4*x+3)^1)/2

((5-9*x)^1)/2-(((4*x+3)^1)/2) = 0

(5-9*x)/2-((4*x+3)/2) = 0

(5-9*x)/2+(-1*(4*x+3))/2 = 0

5-1*(4*x+3)-9*x = 0

2-13*x = 0

(2-13*x)/2 = 0

(2-13*x)/2 = 0 // * 2

2-13*x = 0

2-13*x = 0 // - 2

-13*x = -2 // : -13

x = -2/(-13)

x = 2/13

x = 2/13</span>
4 0
3 years ago
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