Answer:
Answers in order are:
Male
Cell surface
Shape
Sex attractant
Female
Explanation:
Luna Moths are unique species of organisms owing to their remarkable way of communicating sexual. Female Luna moths attract their male counterparts by releasing minute amounts of sexual pheromones, which is detected by the males using their Long antenna and guides him to the female in order for mating to occur.
Based on this, the complete part of the question is in CAPS:
Receptor cells only on the filaments on the ___MALE__ Luna moth’s antennae contain __CELL SURFACE___ molecules that are complementary in __SHAPE___ to __SEX ATTRACTANT___ molecules (sex attractants) produces by the ___FEMALE__ Luna moth.
Answer:
<h2>Chalamydomonas.</h2>
Explanation:
Protists are those organisms that are unicellular and eukaryotic in nature. They are present in diverse forms and structures and show different types of characteristics/. There are many protists that are harmful to human beings and some other organism that causes certain diseases called parasitic protists such as protozoans, trichomonas and some other. There are some protists that are not parasitic in nature such as Chlamydomonas and some other. Protists have different types of the mode of nutrition that may be autotrophic, saprophytic and parasitic and some other.
-Shower with a shorter amount of time
-Fix leaks at home
Answer:
d. disrupt the function of protein kinases involved in cell cycle regulation.
Explanation:
Protein kinases which are useful in cell cycles have major roles in the formation of tumors. So many of these protein kinases go through mutations. Cell cycles would be unable to be stoped and tumor would keep increasing.
A lot of receptors are G protein coupled. So it is going to be really helpful to alter and make G protein receptors to be inactive. Most if these kinases go through means of phosphorylation and dephosphorylation. Targeting these would cause disruption in signal transduction in cells with cancer
Explanation:
Percentage w/v means that weight of solute present in 100 ml of a solution. Hence, 15% w/v means that 15 gram of solute per 100 ml of solution.
Hence, for 2 L (or 2000 mL) preparation the amount of mass will be calculated as follows.
= 300 g
Thus, we can conclude that weight of Tris-HCL required is 300 g.
