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S_A_V [24]
3 years ago
5

5/8+7/8 in simplest form

Mathematics
2 answers:
mote1985 [20]3 years ago
6 0

Step-by-step explanation:

\dfrac{5}{8}+\dfrac{7}{8}=\dfrac{5+7}{8}=\dfrac{12}{8}=\dfrac{12:4}{8:4}=\dfrac{3}{2}=\dfrac{2+1}{2}=\dfrac{2}{2}+\dfrac{1}{2}=1\dfrac{1}{2}

kkurt [141]3 years ago
5 0

Answer:

 1\frac{1}{2}

Step-by-step explanation:

5/8+7/8

--> 12/8

simplify :

--> 3/2

--> 1\frac{1}{2} or 1.5

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4 0
3 years ago
R/3+2=21 solve for r
olchik [2.2K]

Answer:

r=63

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    r/3-(21)=0             r

Simplify   —

           3

r    

 — -  21  = 0

 3     2.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  3  as the denominator :

         21     21 • 3

   21 =  ——  =  ——————

         1        3  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

7 0
3 years ago
7 1/6 = 5 2/5 + p<br><br> p = ???
Crank

\huge\textbf{Hey there!}

\mathbf{7\dfrac{1}{6} = 5\dfrac{2}{5} + p}

\rightarrow\mathbf{7 \dfrac{1}{6} = 5\dfrac{2}{5} + p}

\mathbf{\rightarrow p + 5\dfrac{2}{5}= 7\dfrac{1}{6}}

\mathbf{\rightarrow {p + \dfrac{27}{5}=\dfrac{43}{6}}}

\text{SUBTRACT }\rm{\dfrac{27}{5}}\text{ to BOTH SIDES}

\mathbf{p + \dfrac{27}{5} - \dfrac{27}{5} = \dfrac{43}{6}- \dfrac{27}{5}}

\text{CANCEL out: }\rm{\dfrac{27}{5} - \dfrac{27}{5}}\text{ because it gives you 0}

\text{KEEP: }\rm{\dfrac{43}{6} - \dfrac{27}{5}}\text{ because it help solve for the p-value}

\text{NEW EQUATION: }\rm{p = \dfrac{43}{6} - \dfrac{27}{5}}

\large\textsf{SIMPLIFY IT!}

\mathbf{p = \dfrac{53}{30} \approx p = 1\dfrac{23}{30}}

\huge\boxed{\textsf{Therefore, your answer is: \boxed{\mathsf{p = 1\dfrac{23}{30}}}}}\huge\checkmark

\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}

~\frak{Amphitrite1040:)}

3 0
2 years ago
Read 2 more answers
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