When finding the domain of a square root, you have to know that it is impossible to get the square root of 0 or any negative number. since domain is possible x values this means that x cannot be 0 or any number less than 0. However, you can find the square root of the smallest most infinitely small number greater than 0. since an infinitely small number close to zero can not be written out, we must must say that the domain starts at 0 exclusive. exclusive is represented by an open or close parenthesis so in this case the domain starts with:
(0,
we can get the square root of any number larger than 0 up to infinity but infinity can never be reached so it is also exclusive. So so the ending of our domain would be:
,infinity)
So the answer if the square root is only over the x the answer is
(0, infinity)
But if the square root is over the x- 5 then this would brIng a smaller amount of possible x values. since anything under the square root sign has to be greater than 0, you can say that:
(x - 5) > 0
x > 5
Therefore the domain would start at 5 and the answer would be:
(5, infinity)
Answer:
the answer is 5x
Step-by-step explanation:
I might not know the answer to this question but I hope you find one
PB = 12 (P=1, B=2) Numerical values are assigned to each letter and each letter takes on a single number.
It depends on which variable is eliminated.
If you multiply the second equation by -1 and eliminate the y:
3x - y = 7
-6x + y = -10
-3x = -3 or x = 1
If you multiply the first equation by -2 and eliminate the x:
-6x + 2y = -14
6x - y = 10
y = -4
