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Paladinen [302]
3 years ago
5

Circumference or area how many times must a horse go around a horse walker to walk 1 mile

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
5 0

Answer:

circumference

Step-by-step explanation:

Going around is the circumference

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Find y. (leave answer in simplest radical form) *
egoroff_w [7]

Answer:

12

Step-by-step explanation:

We already found x in a previous problem.

x = 6

The right triangle on the right side with sides x and y is also a 30-60-90 triangle.

The hypotenuse is twice the short leg.

x = 6

y = 2x

y = 12

6 0
3 years ago
George is 1.94 meters tall and wants to find the height of a tree in his yard. He started at the base of the tree and walked 10.
Free_Kalibri [48]
Draw a diagram to illustrate problem as shown below.

Let h = the height of the tree.

Because ΔABC ~ ΔADE, therefore
DE/BC = AD/AB

That is,
h/1.94 = (5.1 + 10.2)/5.1 = 3
h = 1.94*3 = 5.82 m

Answer: 5.82 m

7 0
3 years ago
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katovenus [111]
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8 0
3 years ago
Read 2 more answers
Find the following integral. <br> Integrate x + 5/x^2 +10x +26 dx
sweet-ann [11.9K]

Given :

Polynomial , f(x)=x+\dfrac{5}{x^2}+10x+26 .

To Find :

Integration of f(x) .

Solution :

We know , integration of x^n is :

\int x^n \, dx = \dfrac{x^{n+1}}{n+1}+C

( Here , is C is a constant )

Now ,

\int f(x)\ dx=\int( x+\dfrac{5}{x^2}+10x+26)dx\\                  \\                 \int f(x)\ dx= \int x\ dx+\int 5x^{-2}\ dx+\int 10 x \ dx +26\ dx\\                 \\                 \int f(x)\ dx=\dfrac{x^2}{2}+\dfrac{5\times x^{-1}}{(-1)}+\dfrac{10x^2}{2}+26x+C\\\\                 \int f(x)\ dx=\dfrac{11x^2}{2}+26x-5x^{-1}+C

Therefore , the integration is \dfrac{11x^2}{2}+26x-5x^{-1}+C .

Hence , this is the required solution .

6 0
3 years ago
9:45 on Tuesday Questions
nirvana33 [79]

Answer:

Alternate Exterior Angles

Step-by-step explanation:

The alternate exterior angle theorem is when two different lines are corssed by a transversal. Essentially alternate exterior angles are when two different angles are on opposite sides of the transversal. In the given photo, 6 and 12 are on opposite sides of one transversal which makes them alternate exterior angles.

Best of Luck!

6 0
3 years ago
Read 2 more answers
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