Answer:
A. K = 59.5
Explanation:
Hello there!
In this case, since this reaction seems to start moving leftwards due to the fact that neither A nor Y are present at equilibrium, we should rewrite the equation:
3C (g) + D (g) <-- --> 2A (g) + Y (g)
Thus, the equilibrium expression is:
![K^{left}=\frac{[A]^2[Y]}{[C]^3[D]}](https://tex.z-dn.net/?f=K%5E%7Bleft%7D%3D%5Cfrac%7B%5BA%5D%5E2%5BY%5D%7D%7B%5BC%5D%5E3%5BD%5D%7D)
Next, according to an ICE table for this reaction, we find that:
![[A]=2x](https://tex.z-dn.net/?f=%5BA%5D%3D2x)
![[Y]=x](https://tex.z-dn.net/?f=%5BY%5D%3Dx)
![[C]=0.651M-3x](https://tex.z-dn.net/?f=%5BC%5D%3D0.651M-3x)
![[D]=0.754M-x](https://tex.z-dn.net/?f=%5BD%5D%3D0.754M-x)
Whereas x is calculated by knowing that the [C] at equilibrium is 0.456M; thus:

Next, we compute the rest of the concentrations:
![[A]=2(0.065M)=0.13M](https://tex.z-dn.net/?f=%5BA%5D%3D2%280.065M%29%3D0.13M)
![[Y]=0.065M](https://tex.z-dn.net/?f=%5BY%5D%3D0.065M)
![[D]=0.754M-0.065M=0.689M](https://tex.z-dn.net/?f=%5BD%5D%3D0.754M-0.065M%3D0.689M)
Thus, the equilibrium constant for the leftwards reaction is:

Nonetheless, we need the equilibrium reaction for the rightwards reaction; thus, we take the inverse to get:

Therefore, the answer would be A. K = 59.5.
Regards!
Answer:
<u>3.16 liters O2</u>
Explanation:
I'll assume the C3H3 is really supposed to read C3H8, for propane.
C3H3(g) + 5 O2 (g) + 3 CO2 (g)+ 4 H20 (g)
<u>C3H</u><em><u>8</u></em><u>(g) + 5 O2 (g) + 3 CO2 (g)+ 4 H20 (g)</u>
It is unlikely that all the gases involved in this reaction will remain at STP due to the large amount of energy released, we'll assume STP since:
1) We are told STP and no other information is given, and
2) STP makes the problem much easier, since all gasses occupy 22.4 liters per mole of that gas.
The balanced equation tells us we need 5 moles of O2 for every 1 mole of C3H3: a molar ratio of 5/1 (moles O2/moles C3H8).
Calculate moles C3H8 in 0.632 liters of the stuff [metric term for compound]:
(0.632 liters)/(22.4 liters/mole) = 0.0282 moles C3H8
This means we'll need 5 times that number for the amount of O2 required. That comes to 0.1411 moles O2.
Convert that to volume: (0.1411 moles O2)*(22.4 liter/mole) = 3.16 liters O2
Usually the controlled experiment is the one that is not tested so they look at the experimental experiment to find the differences. Sorry if this doesn't answer your question.
Remember this:
atomic mass= atomic number + number of neutrons
The atomic number (same thing as number of protons) in this case is 15. The atomic mass is 31.
So, we subtract 15 from 31 to find the number of neutrons.
31-15=16
16 neutrons!!!