Answer:
5.77 L
Solution:
Data Given:
Moles = n = 0.24 mol
Temperature = T = 35 °C + 273 = 308 K
Pressure = P = 1.05 atm
Volume = V = ?
Formula Used:
Let's assume that the hydrogen gas in balloon is acting as an Ideal gas, the according to Ideal Gas Equation,
P V = n R T
where; R = Universal Gas Constant = 0.082057 atm.L.mol⁻¹.K⁻¹
Solving Equation for V,
V = n R T / P
Putting Values,
V = (0.24 mol × 0.082057 atm.L.mol⁻¹.K⁻¹ × 308 K) ÷ 1.05 atm
V = 5.77 L
Answer:
Concentric circles of contour lines indicate a hilltop; concentric circles with hachure marks indicate a close depression.
Explanation:
Hope this helped Mark BRAINLIEST!!!
Answer:
Molar solubility is 1.12x10⁻⁴M
Explanation:
The dissolution of magnesium hydroxide is:
Mg(OH)₂(s) ⇄ Mg²⁺ + 2OH⁻
The molar solubility represents the moles of the solid that the solution can dissolve, that could be written as:
Mg(OH)₂(s) ⇄ X + 2X
<em>Where X is solubility.</em>
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If you obtained a [OH⁻] = 2.24x10⁻⁴M and you know [OH⁻] = 2X:
2X = 2.24x10⁻⁴M
X = 2.24x10⁻⁴M/2
X =1.12x10⁻⁴M
<h3>Molar solubility is 1.12x10⁻⁴M</h3>
4Fe+3O₂⇒2Fe₂O₃
CO₂+2Cl₂⇒O₂+CCl₄
<h3>Further explanation </h3>
Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:
1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.
2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product
3. Select the coefficient of the substance with the most complex chemical formula equal to 1
For simple equations, you can experiment with the balance of the number of atoms on the left and right
4Fe+3O₂⇒2Fe₂O₃
CO₂+2Cl₂⇒O₂+CCl₄
aFe+bO₂⇒Fe₂O₃
Fe , left=a, right=2⇒a=2
O, left=2b, right=3⇒2b=3⇒b=3/2
the equation :
2Fe+3/2O₂⇒Fe₂O₃ x2
4Fe+3O₂⇒2Fe₂O₃
aCO₂+bCl₂⇒O₂+CCl₄
C, left=a, right=1⇒a=1
Cl, left=2b, right=4⇒b=2
O, left=2a, right=2⇒2a=2⇒a=1
the equation :
CO₂+2Cl₂⇒O₂+CCl₄
Answer:
mass CaI2 = 23.424 Kg
Explanation:
From the periodic table we obtain for CaI2:
⇒ molecular mass CaI2: 40.078 + ((2)(126.90)) = 293.878 g/mol
∴ mol CaI2 = (4.80 E25 units )×(mol/6.022 E23 units) = 79.708 mol CaI2
⇒ mass CaI2 = (79.708 mol CaI2)×(293.878 g/mol) = 23424.43 g
⇒ mass CaI2 = 23.424 Kg
