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3 years ago

An atom that contains 22 protons,

Chemistry

2 answers:

REY [17]3 years ago

7 0

Answer:

the atom mass number is 45 because 22+23 = 45

Explanation:

Westkost [7]3 years ago

6 0

Answer: 45

Explanation:

Recall that mass number = number of protons + number of neutrons. Hence, the mass number of the atom

= 22 + 23

= 45

Furthermore, the atomic number is equal to the number of protons. Hence, since the number of protons is 22. the atom has an atomic number of 22

Thus, An atom that contains 22 protons,

23 neutrons, and 22 electrons would have a mass of approximately 45

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The reaction of nitrogen dioxide with fluorine

andrew-mc [135]

Answer:

Rate = 0.001615 Ms-1

Explanation:

2 NO2 + F2 --> 2 NO2F

The reaction is first order with respect to NO2 and also first order with respect to F2.

The rate law is given as;

Rate = k [NO2] [ F2]

k = 1.58E-4 M-1s-1

[NO2] = 2.84 M

[F2] = 3.60 M

Rate = ?

Inserting the values into the equation, we have;

Rate = 1.58E-4 * 2.84 * 3.60

Rate = 0.001615 Ms-1

4 0

3 years ago

3. How can you decrease the pressure of a gas in a container without changing the volume of the gas?

inna [77]

Answer:

reduce the temperature of the gas

Explanation:

when you reduce the temperature of the gas the pressure will decrease

8 0

3 years ago

Convert 1.75 g/mL to the unit g/m3. Answer Choices: (1.75 x 106 g/m3), (1.75 x 102 g/m3), (1.75 x 10-2 g/m3), (1.75 x 10-6 g/m3)

Marta_Voda [28]

Answer : 1750000g/cm3

4 0

4 years ago

Eading and

4vir4ik [10]

Answer: 25.8 g of $Cl_2$ will be produced from the decomposition of 73.4 g of $AuCl_3$

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} AuCl_3=\frac{73.4g}{303g/mol}=0.242moles$

The balanced chemical reaction is:

$2AuCl_3\rightarrow 2Au+3Cl_2$

According to stoichiometry :

2 moles of $AuCl_3$ produce = 3 moles of $Cl_2$

Thus 0.242 moles of will produce= $\frac{3}{2}\times 0.242=0.363mol$ of $Cl_2$

Mass of $Cl_2$ = $moles\times {\text {Molar mass}}=0.363mol\times 71g/mol=25.8g$

Thus 25.8 g of $Cl_2$ will be produced from the decomposition of 73.4 g of $AuCl_3$

5 0

3 years ago

Ou have a 5 ml sample of a protein in 0.5 m nacl. you place the protein/salt sample inside dialysis tubing (see fig. 2-14) and p

Oduvanchick [21]

Answer:

Procedure (2)

Explanation:

Assume the dialyses come to equilibrium in the allotted times.

Procedure (1)

If you are dialyzing 5 mL of sample against 4 L of water, the concentration of NaCl will be decreased by a factor of

$\dfrac{5}{4000} = \dfrac{1}{800}$

Procedure (2)

For the first dialysis, the factor is

$\dfrac{5}{1000} = \dfrac{1}{200}$

After a second dialysis, the original concentration of NaCl will be reduced by a factor of

$\dfrac{1}{200} \times \dfrac{1}{200} = \dfrac{1}{40000}$

Procedure (2) is more efficient by a factor of

$\dfrac{40000}{800} = \mathbf{50}$

4 0

3 years ago