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2 years ago

Find k if 3k, k-2, and k + 7 are consecutive terms of an arithmetic sequence.

Mathematics

1 answer:

ahrayia [7]2 years ago

6 0

This is 1:25 (C)

Explanation:

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N76 [4]

1 A. 5

1 B. 12.9

2. For this one, u can write any number less than 4.7, which could be 3, 2, -100, 1.21, etc.

3. For this one, u can write any number greater than (positive!) 2.6, such as 10, 30, 3.1415, etc.

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2 years ago

I need help with this, neither of my parents can help me and i want to understand.

olga2289 [7]

Answer:

See explanation

Step-by-step explanation:

1. To rewrite the expression

$(4^{\frac{2}{5}})^{\frac{1}{4}},$

use exponents property

$(a^m)^n=a^{m\cdot n}$

So,

$(4^{\frac{2}{5}})^{\frac{1}{4}}=4^{\frac{2}{5}\cdot \frac{1}{4}}=4^{\frac{2}{20}}=4^{\frac{1}{10}}$

2. Why $10^{\frac{1}{3}}=\sqrt[3]{10}?$

Raise both sides to 10 power:

$(10^{\frac{1}{3}})^3=10^{\frac{1}{3}\cdot 3}=10^1=10\\ \\(\sqrt[3]{10})^3=10$

So,

$(10^{\frac{1}{3}})^3=(\sqrt[3]{10} )^3$

3. Simplify $\dfrac{3^4}{9}$

Use the Quotient of Powers Property:

$\dfrac{a^m}{a^n}=a^{m-n}$

Then

$\dfrac{3^4}{9}=\dfrac{3^4}{3^2}=3^{4-2}=3^2$

4. Solve $4\sqrt{2}+5\sqrt{4}$

First, note that $\sqrt{4}=2,$ then

$4\sqrt{2}+5\sqrt{4}=4\sqrt{2}+5\cdot 2=4\sqrt{2}+10$

Number $4\sqrt{2}$ is irrational number, number 10 is rational number. The sum of irrational and rational numbers is irrational number.

5. The same as option 4.

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2 years ago