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ch4aika [34]
2 years ago
11

Solve the equation for all values of x. Not really sure how to do this? cos x = 3*cos x - 2

Mathematics
1 answer:
I am Lyosha [343]2 years ago
5 0
\bf cos(x)=3cos(x)-2\implies 0=3cos(x)-2-cos(x)
\\\\\\
0=2cos(x)-2\implies 2=2cos(x)\implies \cfrac{2}{2}=cos(x)\implies 1=cos(x)
\\\\\\
cos^{-1}(1)=\measuredangle x\implies \measuredangle x=
\begin{cases}
0\\
2\pi 
\end{cases}
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Which statement is not true for a binomial distribution with n = 15 and p = 1/20 ? a) The standard deviation is 0.8441 b) The nu
malfutka [58]

Answer:

d) The highest probability occurs when x equals 0.7500

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability, given by the following formula:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

In this problem, we have that:

n = 15, p = \frac{1}{20}

a) The standard deviation is 0.8441

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15*0.05*0.95} = 0.8441

This is correct

b) The number of trials is equal to 15

n is the number of trials and n = 15. So this option is correct.

c) The probability that x equals 1 is 0.3658

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{15,1}.(0.05)^{1}.(0.95)^{14} = 0.3658

This option is correct.

d) The highest probability occurs when x equals 0.7500

False. The number of sucesses is a discrete number, that is, 0, 1, 2,...,15. P(X = 0.75), for example, does not exist.

e) The mean equals 0.7500

E(X) = np = 15*0.05 = 0.75

This option is correct.

f) None of the above

d is false

3 0
2 years ago
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