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algol [13]
2 years ago
13

Liliana and Marcus are playing a word game. Liliana spells a word incorrectly and loses 18 points. Then Marcus spells a word cor

rectly and has the opposite score. Which is the correct way to represent “the opposite of Liliana’s score is equal to Marcus’s score”?
Negative 18 = 18
Negative (negative 18) = negative 18
Negative (18) = negative 18
Mathematics
1 answer:
Pepsi [2]2 years ago
3 0

Answer:

Well if Liliana loses 18 points and Marcus get the correct one and gains 18 points

Step-by-step explanation:

So basically it's going to be negative because its saying what is the opposite of Liliana's core but in reverse order

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A researcher planned a study in which a crucial step was offering participants a food reward. It was important that three food r
lbvjy [14]

Answer:

Step-by-step explanation:

Hello!

A pilot study was conducted to test if three food rewards are equally appealing to the participants.

Of 60 participants surveyed:

16 preferred cupcakes (CC)

26 preferred candy bars (CB)

18 preferred dried apricots (DA)

If the three types of food are equally appealing for the participants, you'd expect that their proportions will be equal: P(CC)=P(CB)=P(DA)= 1/3

1.

The objective of this pilot study is to test if the observed frequencies follow a theoretical model/ distribution. To analyze this, you have to apply a Chi Square Goodness to Fit test. X^2=sum \frac{(O_i-E_i)^2}{E_i} ~~X^2_{k-1} Where k= number of categories of the variable.

For this example the statistical hypotheses are:

H₀: P(CC)=P(CB)=P(DA)= 1/3

H₁: At least one of the proportions isn't equal to the others.

2.

To calculate the expected frequencies for each category you have to use the formula: E_i= n* P_i where Pi represents the theoretical proportion for the i category, stated in the null hypothesis.

E_{CC}= n* P(CC)= 60*1/3= 20

E_{CB}= n*P(CB)= 60*1/3= 20

E_{DA}= n* P(DA)= 60* 1/3= 20

3.

The cutoff or critical value indicates the beginning of the rejection region for the hypothesis test. For the Chi-Square tests, the rejection region is always one-tailed to the right, meaning that you'll reject the null hypothesis if the value of the statistic is big. For the goodness to fit test you have k-1 degrees of freedom, so the critical value will be:

Assuming α: 0.05

X^2_{k-1;1-\alpha /2}= X^2_{2;0.975}= 7.378

The rejection region is then X²₂ ≥ 7.378

4.

X^2_{H_0}= \frac{(O_{CC}-E_{CC})^2}{E_{CC}} + \frac{(O_{CB}-E_{CB})^2}{E_{CB}}  + \frac{(O_{DA}-E_{DA})^2}{E_{DA}} = \frac{(16-20)^2}{20} +\frac{(26-20)^2}{20} +\frac{(18-20)^2}{20}=  \frac{14}{5}= 2.8

I hope this helps!

5 0
3 years ago
PLEASE ANSWER QUCIK I WILL GIVE BRAINLIEST
Fantom [35]

Answer:

1/16

Step-by-step explanation:

4 0
3 years ago
Suppose that J and K are points on the number line.
rodikova [14]

Answer:

-7, -27

Step-by-step explanation:

J is at -17. K is 10 units from J.

Start at point J, -17:

a) If you go 10 units to the right, you end up at -17 + 10 = -7

b) If you go 10 units to the left, you end up at -17 - 10 = -27

J can be at -7 or at -27

Answer: -7, -27

8 0
3 years ago
For 20 Points. 3 Qs.<br> I also gave you guys a help sheet. PLEASE HELP.
Eduardwww [97]
Wat is help sheet, didn't help,

instructions unclear, got my calculator stuck in the ceiling fan

remember some simple exponential laws
( x^{n} )(x^{m})=x^{n+m} and
\frac{x^{n}}{x^{m}} =x^{ n-m }
x^{-m}= \frac{1}{x^{m}}

first one
(2^{-6})(2^{3})=2^{-6+3}=2^{-3}= \frac{1}{2^{3}}  = \frac{1}{8}

2nd one
\frac{7^{5}}{7^{3}} =7^{ 5-3 } = 7^{2} = 49

third one
(3^{-4})(3^{2})=3^{-4+2}=3^{-2}= \frac{1}{3^{2}}  = \frac{1}{9}


dunno wat to do with 'help sheet'

4 0
3 years ago
Bruce buys a trampoline prices at $54. if the sales tax is 3 2/5% how much tax will bruce pay
MrRa [10]
$1.836 round off to $1.84 tax on $54 product with tax of 3.4%
4 0
3 years ago
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