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3 years ago

6

Help with b? Lol I nOOb

2 answers:

lesya [120]3 years ago

7 0

Answer:

give him brainliest noob

Step-by-step explanation:

Rasek [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Since Ms. Snow had all her students that were present participate in the survey the number of how many x is the number of students that were present. The number of x is 24, so 24 students were present that day. Since two students were absent add 2 to 24, which is 26 and the number of students enrolled in the class.

present (took the survey) + absent = total enrolled

24 + 2 = 26

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Given: UR ∥ ST ∠R, ∠T right angles Prove: ∆RSU ≅ ∆TUS

attashe74 [19]

Here

Angle R = Angle T

UR = ST

US = SU

So using RHS conguerence criteria Triangle RSU conguerent to Triangle TUS

8 0

3 years ago

work out the area of a circle with diameter 1.8cm take pie to be 3.142 and give your answer to 1 decimal place.

Masja [62]

Area of a circle = Pi x r^2
Area = Pi x 3.24
Area = 10.18...
Area = 10.2 cm

6 0

3 years ago

La base de una cartulina rectangular mide 8 cm de altura si le recortamos 3 cm a su altura el area de la nueva cartulina seria 1

aev [14]

Answer:

$w=8cm\\h=18.75cm$

Step-by-step explanation:

Let:

$w=Width\\h=Initial\hspace{3}height\\h_m=Modified\hspace{3}height\\\\Where:\\\\h_m=h-3$

The area of the cardboard can be calculated using the formula to find the area of a rectangle:

$A=w*h$

The area of the new cardboard would be:

$A=w*h_m\\\\Where:\\\\w=8\\h_m=h-3\\A=126$

So:

$126=8*(h-3)\\\\126=8h-24$

Solving for h:

$126+24=8h\\\\150=8h\\\\h=\frac{150}{8} =\frac{75}{4} =18.75cm$

Therefore, the dimensions of the initial cardboard are:

$w=8cm\\h=18.75cm$

<u><em>Translation:</em></u>

Sea:

$w=Ancho\\h=Altura\hspace{3}inicial\\h_m=Altura\hspace{3}modificada\\\\Donde:\\\\h_m=h-3$

El área de la cartulina se puede calcular usando la fórmula para encontrar el área de un rectángulo:

$A=w*h$

El área de la nueva cartulina sería:

$A=w*h_m\\\\Donde:\\\\w=8\\h_m=h-3\\A=126$

Entonces:

$126=8*(h-3)\\\\126=8h-24$

Resolviendo para h:

$126+24=8h\\\\150=8h\\\\h=\frac{150}{8} =\frac{75}{4} =18.75cm$

Por lo tanto, las dimensiones de la cartulina inicial son:

$w=8cm\\h=18.75cm$

7 0

3 years ago

I need domain and range

VikaD [51]

Answer:

Step-by-step explanation:

Range from - infinite to - 2

The domain from - infinite to 5

8 0

3 years ago

Gomez spent 5/8 of his money on a gift for his brother and 1/6 of his money on a card. He saved the rest of his money

Sergio [31]

He saved 5/24 of his money

Make common denominators
1/6 * 4/4 =4/24
5/8 * 3/3= 15/24

15/24 + 4/24 = 19/24

24/24 - 19/24
= 5/24

3 0

3 years ago