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Ymorist [56]
2 years ago
15

What is 66 2/3 % times $48

Mathematics
1 answer:
katovenus [111]2 years ago
7 0

Answer:

the answer should be 32$

Step-by-step explanation:

i rlly hope this helps

You might be interested in
What is the sum of (2x+4)+(-3x+9)
Levart [38]

Answer:

-x + 13

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define expression</u>

(2x + 4) + (-3x + 9)

<u>Step 2: Simplify</u>

  1. Combine like terms (x):                    -x + 4 + 9
  2. Combine like terms (Z):                    -x + 13
7 0
2 years ago
Read 2 more answers
HELP I NEED HELP ASAP
Kaylis [27]

Answer:

so how many units are they away from each other

Step-by-step explanation:1,

1.1-2.0  how many units are they away from each other

u could drag the number from the top to the chart below

good luck!

6 0
3 years ago
Which of the following is the product of the rational expression shown below
wolverine [178]

Option C: \frac{x^{2}-9}{x^{2}-4} is the product of the rational expression.

Explanation:

The given rational expression is \frac{x+3}{x+2} \cdot \frac{x-3}{x-2}

We need to determine the product of the rational expression.

<u>Product of the rational expression:</u>

Let us multiply the rational expression to determine the product of the rational expression.

Thus, we have;

\frac{(x+3)(x-3)}{(x+2)(x-2)}

Let us use the identity (a+b)(a-b)=a^2-b^2 in the above expression.

Thus, we get;

\frac{x^{2} -3^2}{x^{2} -2^2}

Simplifying the terms, we get;

\frac{x^{2}-9}{x^{2}-4}

Thus, the product of the rational expression is \frac{x^{2}-9}{x^{2}-4}

Hence, Option C is the correct answer.

6 0
3 years ago
An article reports the following data on yield (y), mean temperature over the period between date of coming into hops and date o
skelet666 [1.2K]

Answer:

x1=c(16.7,17.4,18.4,16.8,18.9,17.1,17.3,18.2,21.3,21.2,20.7,18.5)

x2=c(30,42,47,47,43,41,48,44,43,50,56,60)

y=c(210,110,103,103,91,76,73,70,68,53,45,31)

mod=lm(y~x1+x2)

summary(mod)

R output: Call:

lm(formula = y ~ x1 + x2)

Residuals:  

   Min      1Q Median      3Q     Max

-41.730 -12.174   0.791 12.374 40.093

Coefficients:

        Estimate Std. Error t value Pr(>|t|)    

(Intercept) 415.113     82.517   5.031 0.000709 ***  

x1            -6.593      4.859 -1.357 0.207913    

x2            -4.504      1.071 -4.204 0.002292 **  

---  

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1  

Residual standard error: 24.45 on 9 degrees of freedom  

Multiple R-squared: 0.768,     Adjusted R-squared: 0.7164  

F-statistic: 14.9 on 2 and 9 DF, p-value: 0.001395

a).  y=415.113 +(-6.593)x1 +(-4.504)x2

b). s=24.45

c).  y =415.113 +(-6.593)*21.3 +(-4.504)*43 =81.0101

residual =68-81.0101 = -13.0101

d). F=14.9

P=0.0014

There is convincing evidence at least one of the explanatory variables is significant predictor of the response.

e).  newdata=data.frame(x1=21.3, x2=43)

# confidence interval

predict(mod, newdata, interval="confidence")

#prediction interval

predict(mod, newdata, interval="predict")

confidence interval

> predict(mod, newdata, interval="confidence",level=.95)

      fit      lwr      upr

1 81.03364 43.52379 118.5435

95% CI = (43.52, 118.54)

f).  #prediction interval

> predict(mod, newdata, interval="predict",level=.95)

      fit      lwr      upr

1 81.03364 14.19586 147.8714

95% PI=(14.20, 147.87)

g).  No, there is not evidence this factor is significant. It should be dropped from the model.

4 0
2 years ago
This is due today, and I have no idea what I'm doing, please help if you know anything.
defon

Binomial distribution formula: P(x) = (n  k) p^k * (1 - p)^n - k

a) Probability that four parts are defective = 0.01374

P(4 defective) = (25 4) (0.04)^4 * (0.96)^21

P(4 defective) = 0.01374

b) Probability that at least one part is defective = 0.6396

Find the probability that 0 parts are defective and subtract that probability from 1.

P(0 defective) = (25 0) (0.04)^0 * (0.96)^25

P(0 defective) = 0.3604

1 - 0.3604 = 0.6396

c) Probability that 25 parts are defective = approximately 0

P(25 defective) = (25 25) (0.04)^25 * (0.96)^0

P(25 defective) = approximately 0

d) Probability that at most 1 part is defective = 0.7358

Find the probability that 0 and 1 parts are defective and add them together.

P(0 defective) = 0.3604 (from above)

P(1 defective) = (25 1) (0.04)^1 * (0.96)^24

P(1 defective) = 0.3754

P(at most 1 defective) = 0.3604 + 0.3754 = 0.7358

e) Mean = 1 | Standard Deviation = 0.9798

mean = n * p

mean = 25 * 0.04 = 1

stdev = \sqrt{np(1-p)}

stdev = \sqrt{(25)(0.04)(1-0.04)} = 0.9798

Hope this helps!! :)

7 0
3 years ago
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