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Rina8888 [55]
3 years ago
5

A dripping tap wastes 11,250 ml of water in 9 hours. If it drips equal quantity in each hour ,how much water will be wasted in a

n hour? Express your answer in L.
Mathematics
1 answer:
EastWind [94]3 years ago
4 0

Answer: In 1 hour , it will waste = 1.25ml

Step-by-step explanation:

Volume of water  wasted by the tap in 9 Hours = 11,250 ml

Since  it drips in equal quantity,

In 1 hr , it will drip=  1 x 11,250 / 9 = 1,250 ml

But  1000 ml = 1 Liter

1250 ml = 1250ml x 1Liter / 1000ml= 1.25L

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A =10<br> a/4 + 1/3 <br> How do I figure out this answer?
masya89 [10]

Answer:

1 6/11

Step-by-step explanation:

10/4 + 1/3. 30/12 + 4/12 =34/22 = 17/11 = 1 6/11. 10/4 ×3/3 =30/12. 1/4 × 4/4 =4/12. 34/22 ÷2/2 = 17/11 = 1 6/11

3 0
3 years ago
Joe gave 1/4 of his total candies to his classmate then he gave 4/6 of when he had left to his brother when he went home then he
Makovka662 [10]

Answer:

112

Step-by-step explanation:

Given: Joe gave 1/4 of his total candies to his classmate.

            Then, he gave 4/6 of when he had left to his brother.

             He gave 25% of the remaining candies to his sister.

             Finally, he only had 21 candies left.

Lets assume the total number of candies at the beginning be "x".

First, finding the number candies left after giving candies to classmate.

∴ Remaining candies=  x- x\times \frac{1}{4}

Solving it to find remaining candies after giving candies to clasmate.

⇒ Remaining candies= x-\frac{x}{4}

Taking LCD as 4

⇒ Remaining candies= \frac{4x-x}{4} = \frac{3x}{4}

∴ Remaining candies after giving candies to clasmate= \frac{3x}{4}

now, finding the candies left after giving candies to his brother.

∴ Remaining candies= \frac{3x}{4} - \frac{3x}{4} \times \frac{4}{6}

Solving it to find the remaining candies after giving candies to his brother.

⇒ Remaining candies= \frac{3x}{4} - \frac{x}{2}

Taking LCD 4

⇒ Remaining candies= \frac{3x-2x}{4} = \frac{x}{4}

∴ Remaining candies after giving candies to his brother= \frac{x}{4}

We know, Joe was left with only 21 candies after giving candies to his sister.

Therefore, putting an equation for remaining candies to find the number of candies at the beginning.

⇒\frac{x}{4} - 25\% \times \frac{x}{4} = 21

⇒\frac{x}{4} - \frac{0.25x}{4} = 21

Taking LCD 4

⇒ \frac{x-0.25x}{4} = 21

⇒ \frac{0.75x}{4} = 21

Multiplying both side by 4

⇒0.75x= 21\times 4

dividing both side by 0.75

⇒x= \frac{21\times 4}{0.75}

∴x= 112

Hence, Joe had 112 candies at the beginning.

6 0
3 years ago
How to write a equation in standard form if slope is 8 and y- intercept is -8
Arlecino [84]
Standard form is Ax+By=C and so the equation in Slope intercept form (y=mx+b) is y=8x- 8 and the equation in standard form is -8x+y= -8
4 0
3 years ago
Who Would Like To Help Me??
ser-zykov [4K]

Answer:

The answer is 128 bunches because 1027/8 = 128.375

Then I multiplied 128*8

which is equal to 1024

So the left over is 3 after subtracting the initial.

8 0
3 years ago
Pizza by the Pan sold 4 dozen pizzas in the afternoon. That night, they sold 2.5 times as many pizzas as they did during the aft
Sav [38]

Answer:

they sold 14 pizzas all day.

Step-by-step explanation:

4 x 2 = 8

0.5 means half of what they sold in the afternoon

4 ÷ 2 = 2

now add them both together to get the number of pizzas they sold at night.

8 + 2 = 10

now add the afternoon and night together

10 + 4 = 14

answer: 14 pizzas

6 0
3 years ago
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