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Marizza181 [45]
3 years ago
15

PLEASE HELP ME. THIS IS DUE TODAY

Mathematics
1 answer:
MakcuM [25]3 years ago
4 0
I think it’s b it only makes since
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At the county fair, Peter wants to ride a rollercoaster that costs 28. tickets, a bumper car that costs 19 tickets, and a merry-
Alisiya [41]

Answer:

(28+19+25)-(32-9)=72-23

=49

8 0
2 years ago
Ralph is 3 times as old as Sara. In 6 years, Ralph will be only twice as old as Sara will be then. Find Ralph's age now.
vovikov84 [41]
R=3*S
in 6 years ⇒R+6=2*(S+6)
3*S+6=2*S+2*6
3S+6=2S+12
3S-2S=12-6
S=6 
R=3*6=18 ( Ralph 's age now)

in 6 years Ralph's age will be 3*x+6

6 0
2 years ago
Helppppp i need help ASAP
algol13

Answer:

a) 10.10 a.m. , (b) 10.20 a.m. which is 10 minutes after sprints start , (c) The students work at 10.50 a.m. , (d) For 60 minutes from 10 a.m. to 11 a.m. which equals to 1 hour

4 0
2 years ago
A baker knows that the daily demand for strawberry pies is a random variable that follows the normal distribution with a mean of
Elan Coil [88]

The demand that has an 8% probability of being exceeded is 38.1230 .

<h3>What is probability?</h3>

Probability is the aspect of mathematics that focus on the occurrence of a random event.

This is calculated below:

The  normal random variable having the  mean is been given as :

(Mu = 31.8)

The standard deviation is been given as ( sd = 4.5)

Then in making our calculation, we will need to make use of the formular below:

\\Z= (X - Mu) / sd = (X - 31.8) / 4.5

But we know that going with the  probability of 0.08

where  k = 1.4051

P (Z > 1.4051)

k = 1.4051

we can have the expression for  k  as [(X - 31.8) / 4.5]

This can be simplified as:

X  = 4.5 (1.4051) + 31.8 = 38.1230.

Therefore, the  demand that has an 8% probability of being exceeded is 38.1230 .

Learn more about normal distribution on:

brainly.com/question/4079902

#SPJ1

5 0
2 years ago
One more question on this test guys. please answer as fast as possible. If you do,
GaryK [48]

1. The given rectangular equation is x=2.

We substitute x=r\cos \theta.

r\cos \theta=2

Divide through by \cos \theta

r=\frac{2}{\cos \theta}

r=2}\sec \theta

\boxed{x=2\to r=2\sec \theta}

2. The given rectangular equation is:

x^2+y^2=36

This is the same as:

x^2+y^2=6^2

We use the relation r^2=x^2+y^2

This implies that:

r^2=6^2

\therefore r=6

\boxed{x^2+y^2=36\to r=6}

3. The given rectangular equation is:

x^2+y^2=2y

This is the same as:

We use the relation r^2=x^2+y^2 and y=r\sin \theta

This implies that:

r^2=2r\sin \theta

Divide through by r

r=2\sin \theta

\boxed{x^2+y^2=2y\to r=2\sin \theta}

4. We have x=\sqrt{3}y

We substitute y=r\sin \theta and x=r\cos \theta

r\cos \theta=r\sin \theta\sqrt{3}

This implies that;

\tan \theta=\frac{\sqrt{3}}{3}

\theta=\frac{\pi}{6}

\boxed{x=\sqrt{3}y\to \theta=\frac{\pi}{6}}

5. We have x=y

We substitute y=r\sin \theta and x=r\cos \theta

r\cos \theta=r\sin \theta

This implies that;

\tan \theta=1

\theta=\frac{\pi}{4}

\boxed{x=y\to \theta=\frac{\pi}{4}}

6 0
3 years ago
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