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3 years ago

Watch help video

Mathematics

1 answer:

alukav5142 [94]3 years ago

7 0

Answer:

<h2>2ucycxc8rfe is a good game song for you and the world is a 3 of the paleozozoic era hseindunusxbeubsuxdb udnxdb you have been given the most </h2>

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PLEASE HELP ME!!!!!

solong [7]

The full workings for the house purchase you made on a mortgage are as follows:

1. Price of House = $499,000 (given)

2. Down Payment = $99,800 ($499,000 x 20%)

3. Amount Financed (Mortgage principal) = $399,200 ($499,000 - $99,800).

4. Monthly Payment = $2,522.94 (given)

5. Number of monthly payments = 360 months (30 x 12)

6. Total Payback = $908,258.40 ($2,522.94 x 360)

7. Total Interest = $509,058.40 ($908,258.40 - $399,200)

8. Assessed Valuation = $199,600 ($499,000 x 40%)

9. Real Estate Taxes (annual) = $6,047.88 ($199,600 x $3.03/$100)

10. Escrow Payment Per month (taxes & insurance) = $628.99 ($6,047.88 + $1,500)/12

11. Monthly Payment to lender (escrow + mortgage) = $3,151.93 ($628.99 + $2,522.94)

<h3>What is a mortgage?</h3>

A mortgage is a loan arrangement that allows a borrower to buy some property, usually a house, without paying for the full cost immediately.

The borrower then makes a monthly payment, which includes the principal and its interest.

Learn more about mortgage payments at brainly.com/question/22846480

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2 years ago

Help please word problem...show work please

Alona [7]

A) you must plug in 50 for variable F and solve for C

C= $\frac{5}{9}$ (50-32)
C= $\frac{5}{9}$ (18)
C= 10
50 degrees fahrenheit is equal to 10 degrees celsius

B) you must solve the equation for F

C= $\frac{5}{9}$ (F-32)
C/ $\frac{5}{9}$ =F-32
C/ $\frac{5}{9}$ +32=F
F= C/ $\frac{5}{9}$ +32

dividing by a fraction is the same as multiplying buy its reciprocal so it can also be written as

F= $\frac{9}{5}$ C +32

now you just plug in 50 for the variable C in the new equation

F= $\frac{9}{5}$ (50) +32
F= 90 + 32
F= 122

50 degrees celsius is equal to 122 degrees fahrenheit

hope this helped!

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3 years ago

How do you find the intersection of two sets?

Vlad [161]

To find the intersection of these two sets, we need to find out what elements they have in common. The numbers 3, 4, 5 are elements of both sets, therefore theintersections of A and B is {3. 4. 5].

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3 years ago

PLEASEE HELPP QUICK!!! QUESTIONS IN THE PICTURESS

Setler [38]

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2 years ago

Read 2 more answers

What are the solutions to the equation

frosja888 [35]

Answer:

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

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3 years ago