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klasskru [66]
3 years ago
9

An exponential growth function has an asymptote of y = –3. Which might have occurred in the original function to permit the rang

e to include negative numbers?
A whole number constant could have been added to the exponential expression.
A whole number constant could have been subtracted from the exponential expression.
A whole number constant could have been added to the exponent.
A whole number constant could have been subtracted from the exponent.
Mathematics
2 answers:
neonofarm [45]3 years ago
5 0

Answer: C. A whole number constant could have been added to the exponent.

Step-by-step explanation: On Edge!

Blababa [14]3 years ago
3 0

The right choice is: A <em>whole</em> number constant could have been <em>subtracted</em> from the <em>exponential</em> expression.

Let be an <em>exponential</em> function of the form y = A\cdot e^{B\cdot x}, where A and B are <em>real</em> numbers. A <em>horizontal</em> asymptote exists when e^{B\cdot x} \to 0, which occurs for B\cdot x \to - \infty.

For this function, the <em>horizontal</em> asymptote is represented by y = 0 and to change the value of the asymptote we must add the <em>parent</em> function by another <em>real</em> number (C), that is to say:

y = A\cdot e^{B\cdot x} + C (1)

In this case, we must use C = -3 to obtain an horizontal asymptote of -3. Thus, the right choice is: A <em>whole</em> number constant could have been <em>subtracted</em> from the <em>exponential</em> expression.

To learn more on asymptotes, we kindly invite to check this verified question: brainly.com/question/8493280

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