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fredd [130]
3 years ago
12

8.9 x 3.8 Give me the answer please

Mathematics
1 answer:
slavikrds [6]3 years ago
5 0

Answer:

<u>33.82</u>

Step-by-step explanation:

8.9 x 3.8 would be 33.82

make brainliest if u want

Hope this helped :)

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In ΔNOP, the measure of ∠P=90°, PO = 48, NP = 55, and ON = 73. What is the value of the sine of ∠N to the nearest hundredth?
mojhsa [17]

Answer:

0.66

Step-by-step explanation:

sin 90°/ 73 = sin <em>L</em><em> </em>N /48

=> sin <em>L</em><em> </em>N = 48×sin90° /73

= 48/73 = 0.66

4 0
3 years ago
Show your solution read the instructions​
Annette [7]

Answer:

1) 5r + 2 < s

2) 12t + 6s < 960

3) p - q > 30

Step-by-step explanation:

1) Length of a ruler = r

Height of Shiela = s

According to the question ,

5 times the length of a ruler increased by 2 .

⇒ 5r + 2

Also , 5r + 2 is less than height of Shiela.

Hence , the linear inequality is ⇒ 5r + 2 < s

2) Let the cost of each t-shirt be 't' & cost of each short be 's'.

⇒ Cost of dozen of t-shirts = 12t and Cost of half a dozen shorts = 6s

According to the question ,

12t & 6s is not greater than Php 960.

Hence the linear inequality is ⇒ 12t + 6s < 960

3) Let the number of Php 100-peso tickets be 'p' and let the number of Php  50-peso tickets be 'q'.

According to the question ,

Difference of p & q is not less than 30

Hence the linear inequality is ⇒p - q > 30

8 0
3 years ago
How do u solve this 5 − (x + 5) −2x + 4)
Luda [366]
5 - (x + 5) - (2x + 4)
5 - x - 5 - 2x - 4
-3x - 4
3 0
3 years ago
Simplify 9x^0y^-3 write your answer using only positive exponents 
Sunny_sXe [5.5K]

Answer:

9x/y³

Step-by-step explanation:

6 0
3 years ago
Every year after a new car is
slavikrds [6]

Answer: The value of the car after 3 years is $5,333.333

And no, the relationship is not linear, is an exponential decay.

Step-by-step explanation:

We know that every year, the car loses 1/3 of its value.

So if the initial value of the car is V.

After one year, the new value of the car will be:

Value (1 year) = V - (1/3)*V = (2/3)*V

After another year, the value will be:

Value (2 years) = (2/3)*V - (1/3)*(2/3)*V = V*(2/3)^2

Ok, we already can see that this is an exponential decay.

(So no, this is not a linear relationship).

The value equation as a function of the number of years will be:

Value(N) = V*(2/3)^N

Then if the initial cost of a car is $18,000, and we want to know its value after 3 years, we need to replace V by $18,000 and N by 3 in the above equation:

Value(3) = $18,000*(2/3)^3 = $5,333.333

6 0
3 years ago
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