Create a graph that has the following<br> Domain and Range:<br> Domain: -5 Range:<br> y

Zanzabum

Answer:is there a question

Step-by-step explanation:

8 0

2 years ago

Megan wants to build a fence around her pool. The pool is 28 feet long by 23 feet wide. The fence is to be 15 feet from the edge

marshall27 [118]

To determine the amount of fencing needed to enclose the pool area, you will need to add 15 feet to both sides of both dimensions to find the new dimensions that will need enclosed.

28 feet + 15 feet + 15 feet = 58 feet

23 feet + 15 feet + 15 feet = 53 feet

The fence will need to be 2 x 58 + 2 x 53 or 222 feet long for the 53 feet by 58 feet area.

5 0

3 years ago

HI pls help ASAP!! 20 points :DD will give brainlest!!

almond37 [142]

The points is 10 bye

4 0

3 years ago

A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s

denpristay [2]

Answer:

For this case the 95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=40-1=39$

For this case the 95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

3 0

4 years ago

(3, r) and (7, 2) m = 1

hammer [34]

Answer:

r = -2

Step-by-step explanation:

2+2 = 4

7-3 = 4

4/4 = 1

m = 1

5 0

3 years ago

Create a graph that has the following Domain and Range: Domain: -5 Range: y > -8