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lyudmila [28]
2 years ago
5

Solve each equation below for x. 2^(x+3)=2^2x 3^5=9^2x 3^(2x+1)=3^3

Mathematics
2 answers:
anzhelika [568]2 years ago
8 0

Answer:

3^5=9^2x = 3

3^(2x+1) =3^3 = 1

Step-by-step explanation:

spayn [35]2 years ago
8 0

Answer:

x=3

x=3

x=1

Step-by-step explanation:

Create equivalent expressions in the equation that all have equal bases, then solve for x.

hope this helped.

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Let 2x-5y=16 and 5x+3y=9. what is the value of 12x+y
kari74 [83]
2x-5y=16    =>10x-25y=80
5x+3y=9     => 10x+6y=18
subtract one from the other: (6-(-25)y=(18-80), 31y=-62, y=-2
plug y=-2 in 2x-5y=16 to find x: 2x+10=16, x=3
12x+y=12*3-2=34
3 0
3 years ago
How do you make 4/3 and 3/3 have a denominator of 5
bagirrra123 [75]

Answer:

Step-by-step explanation:

Actually, you can't.  You could multiply the numerator and denominator of each 4/3 and 3/3 by 5, obtaining:

5(4)          5(3)

------ and --------

5(3)           5(3)

but this result has little practical value.  4/3 and 3/3 could be combined immediately, obtaining 7/3, if that's what you want to do, as the fractions already have the same denominator (3).

6 0
3 years ago
A farmer wants to fence in a rectangular plot of land adjacent to the north wall of his barn. No fencing is needed along the bar
Luba_88 [7]

The dimensions for the plot that would enclose the most area are a length and a width of 125 feet.

In this question we shall use the first and second derivative tests to determine the <em>optimal</em> dimensions of a rectangular plot of land. The perimeter (p), in feet, and the area of the rectangular plot (A), in square feet, of land are described below:

p = 2\cdot (w+l) (1)

A = w\cdot l (2)

Where:

  • w - Width, in feet.
  • l - Length, in feet.

In addition, the cost of fencing of the rectangular plot (C), in monetary units, is:

C = c\cdot p (3)

Where c is the fencing unit cost, in monetary units per foot.

Now we apply (2) and (3) in (1):

p = 2\cdot \left(\frac{A}{l}+l \right)

\frac{C}{c} = 2\cdot (\frac{A}{l}+l )

\frac{C\cdot l}{c} = 2\cdot (A+l^{2})

\frac{C\cdot l}{c}-2\cdot l^{2} = 2\cdot A

\frac{C\cdot l}{2\cdot c} - l^{2} = A (4)

We notice that fencing costs are directly proportional to the area to be fenced. Let suppose that cost is the <em>maximum allowable </em>and we proceed to perform the first and second derivative tests:

FDT

\frac{C}{2\cdot c}-2\cdot l = 0

l = \frac{C}{4\cdot c}

SDT

A'' = -2

Which means that length leads to a <em>maximum</em> area.

If we know that c = 8 and C = 4000, then the dimensions of the rectangular plot of land are, respectively:

l = \frac{4000}{4\cdot (8)}

l = 125\,ft

A = \frac{(4000)\cdot (125)}{2\cdot (8)} -125^{2}

A = 15625\,ft^{2}

w = \frac{15625\,ft^{2}}{125\,ft}

w = 125\,ft

The dimensions for the plot that would enclose the most area are a length and a width of 125 feet.

We kindly invite to check this question on areas: brainly.com/question/11952845

8 0
2 years ago
18 over 4= I need help I been trying to find out what the answer is please help
Oksana_A [137]
18/4 can be simplified into 9/2 or 4 1/2
5 0
3 years ago
The points in the table below are on the graph of the function g(x). Which rule and table A value corresponding points on the gr
kvasek [131]

Answer: C

Step-by-step the table that's flipped the y and x values of the given table

4 0
2 years ago
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