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Ugo [173]
2 years ago
15

Explain plssssssssssssssss

Mathematics
1 answer:
irina [24]2 years ago
7 0
So the problem is asking you to combine equations, in this case the Y factor will cancel out so you will be left with the X factor and the total after you add both of the totals together,
6x-4y=16
5x+4y=6
6x-5x=x
16+6=22
x=22
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6.5x-10=4.5x+6 can someone give a step by step answer plz
Trava [24]

Collect like terms
6.5x-4.5x = 6+10
2x = 6+10
Divide both sides
2x = 16
X= 8
7 0
3 years ago
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What do x and y equal?
olasank [31]
Y is equal to 23 and x is equal to 28. This is because you can move 3y over to the corner to its left that matches the position 3y is in. From there you set 3y + 5y -4 = 180 because the add up to a straight line. Then you get 23 for y and you can use that to make 3y=69. Use the 69 to set it equal to 2x +13 and solve to get x=28.
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3 years ago
5.5% of x =19.84 find x​
Softa [21]

Answer:

ur answer is

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3 years ago
Question 2b only! Evaluate using the definition of the definite integral(that means using the limit of a Riemann sum
lara [203]

Answer:

Hello,

Step-by-step explanation:

We divide the interval [a b] in n equal parts.

\Delta x=\dfrac{b-a}{n} \\\\x_i=a+\Delta x *i \ for\ i=1\ to\ n\\\\y_i=x_i^2=(a+\Delta x *i)^2=a^2+(\Delta x *i)^2+2*a*\Delta x *i\\\\\\Area\ of\ i^{th} \ rectangle=R(x_i)=\Delta x * y_i\\

\displaystyle \sum_{i=1}^{n} R(x_i)=\dfrac{b-a}{n}*\sum_{i=1}^{n}\  (a^2 +(\dfrac{b-a}{n})^2*i^2+2*a*\dfrac{b-a}{n}*i)\\

=(b-a)^2*a^2+(\dfrac{b-a}{n})^3*\dfrac{n(n+1)(2n+1)}{6} +2*a*(\dfrac{b-a}{n})^2*\dfrac{n (n+1)} {2} \\\\\displaystyle \int\limits^a_b {x^2} \, dx = \lim_{n \to \infty} \sum_{i=1}^{n} R(x_i)\\\\=(b-a)*a^2+\dfrac{(b-a)^3 }{3} +a(b-a)^2\\\\=a^2b-a^3+\dfrac{1}{3} (b^3-3ab^2+3a^2b-a^3)+a^3+ab^2-2a^2b\\\\=\dfrac{b^3}{3}-ab^2+ab^2+a^2b+a^2b-2a^2b-\dfrac{a^3}{3}  \\\\\\\boxed{\int\limits^a_b {x^2} \, dx =\dfrac{b^3}{3} -\dfrac{a^3}{3}}\\

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Number 11; What do you have to do to solve it?
taurus [48]

very positive about these results

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