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masya89 [10]
4 years ago
10

Can someone help me please I’m confused!!!

Mathematics
1 answer:
Soloha48 [4]4 years ago
4 0

Answer:

10) -1

11) 1/2 or 0.5

12) -1/5 or -0.2

13) -13/6 or -2.166666666

14) -1/8 or -0.125

15) 1/2 or 0.5

hope it helps;)

good luck!

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I really need help and i need to solve this one that says solve & simplify:3/4×2/3
VARVARA [1.3K]

3/4 2/3

This is a multiplication of fractions

1.- Multiply the numerators and the denominators

3/4 x 2/3 = (3x 2) / (4 x 3)

= 6/12

2.- Simplify

= 3/6

= 1/2

4 0
1 year ago
Use substitution to solve the linear system of equations.
goblinko [34]

Answer:

(4, - 2 )

Step-by-step explanation:

Given the 2 equations

x = 4 → (1)

- y = \frac{1}{2} x → (2)

Substitute x = 4 into (2)

- y = \frac{1}{2} × 4 = 2 ( multiply both sides by - 1 )

y = - 2

Solution = (4, - 2 )

6 0
3 years ago
Which of the following is true of the data set represented by the box plot? (2 points)
sweet [91]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Among the choices provided above the one that is true of the data set represented by the box plot is <span>Removing the outliers would not affect the median.</span>
4 0
3 years ago
Which fraction is closest to zero? 8/12, 5/8, 6/10, 2/3
konstantin123 [22]
6/10 is the closest to zero because if you simplify all the fractions you can, then convert them into decimals, you can easily find what is closer to zero:

8/12 = 2/3 = 0.66
5/8 = 0.62
6/10 = 3/5 = 0.60
2/3 = 0.66

0.60 or 6/10 is the smaller number ;))
5 0
3 years ago
Read 2 more answers
?
yanalaym [24]

Answer:

A=\pi \frac{d^2}{4}

Step-by-step explanation:

The typical equation for the area of a circle is A=\pi r^2. Since the answer choices are in terms of <em>d</em>, the diameter of the circle, you will need to find <em>r</em> in terms of <em>d</em>.

To find <em>r</em> in terms of <em>d</em>, you know that the diameter of a circle is two times its radius. As an equation, this is

d=2r, or solving for <em>r</em>,

r = \frac{d}{2}.

Now that you have an equation for <em>r</em> in terms of <em>d, </em>you can substitute <em>r</em> with \frac{d}{2} from the original equation.

A=\pi r^2

A=\pi (\frac{d}{2})^2

A=\pi \frac{d^2}{4}

4 0
3 years ago
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