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PIT_PIT [208]
2 years ago
5

Type the correct answer in the box. Write your answer as a whole number. The radius of the base of a cylinder is 10 centimeters,

and its height is 20 centimeters. A cone is used to fill the cylinder with water. The radius of the cone's base is 5 centimeters, and its height is 10 centimeters. The number of times one needs to use the completely filled cone to completely fill the cylinder with water is . Reset Next
Mathematics
1 answer:
konstantin123 [22]2 years ago
6 0

The number of times one needs to use the completely filled cone to completely fill the cylinder with water 24 times

<h3>How to find the volume of a cylinder and cone?</h3>

volume of a cylinder = πr²h

volume of a cylinder = 3.14 × 10² × 20

volume of a cylinder = 6280 cm³

volume of the cone = 1 / 3 πr²h

volume of the cone = 1 / 3 × 3.14 × 5² × 10

volume of the cone = 261.666666667

volume of the cone = 261.7 cm³

Therefore, the number of times one needs to use the completely filled cone to completely fill the cylinder with water is as follows:

number of time = 6280 / 261.7 = 23.9969430646

number of time = 24 times

learn more on volume here: brainly.com/question/1578538

#SPJ1

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Answer:

t=\frac{5.63-5}{\frac{1.61}{\sqrt{15}}}=1.516  

df=n-1=15-1=14  

Since is a right tailed test the p value would be:  

p_v =P(t_{14}>1.516)=0.076  

If we use a significance level of 0.05 we see that p_v > \alpha and then we can conclude that we don't have evidence in order to conclude that the mean is higher than 5.63, so then the claim makes sense.

Step-by-step explanation:

Data given and notation  

\bar X=5.63 represent the sample mean  

s=1.61 represent the standard deviation for the sample  

n=15 sample size  

\mu_o =15/tex] represent the value that we want to test  &#10;[tex]\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the average is more than 5.63, the system of hypothesis would be:  

Null hypothesis:\mu \leq 5.63  

Alternative hypothesis:\mu > 5.63  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{5.63-5}{\frac{1.61}{\sqrt{15}}}=1.516  

Now we need to find the degrees of freedom for the t distribution given by:

df=n-1=15-1=14  

P value

Since is a right tailed test the p value would be:  

p_v =P(t_{14}>1.516)=0.076  

If we use a significance level of 0.05 we see that p_v > \alpha and then we can conclude that we don't have evidence in order to conclude that the mean is higher than 5.63, so then the claim makes sense.

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Answer:

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Step-by-step explanation:

It is given that the figure A'B'C'D' is a dilation of figure ABCD.

We know that after dilation the corresponding sides of image and preimage are in the same proportion.

The image of AD is A'D'.

From the figure it is noticed that the A(-1,2), D(-1,-1), A'(-3,6) and D'(-3,-3).

Distance formula is

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