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3 years ago

I'm so confused, pls help

Mathematics

1 answer:

Vera_Pavlovna [14]3 years ago

8 0

Answer:

x = 14 D

Step-by-step explanation:

(18x + 36) / 3 = 6x + 12

6x + 12 = -16 + 8x

-6x . -6x

12 = -16 + 2x

+16 . +16

28 = 2x

/2 . /2

14 = x

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victor wants to make a book tower of height 4m. If the thickness of each book is 50 cm how many will he need to make the desired

igor_vitrenko [27]

Answer:

Explained below

Step-by-step explanation:

We know (hopefully) that 100 centimeters is equal to 1 meter.

The expression should essentially be 400/50.

400/50 = 8

Victor would need 8 books to make a tower with the height of 4 meters.

By the way 50 centimeters per book is a pretty hefty book, would be as thick as my hand pointing upwards.

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2 years ago

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Please help me with this problem

Alenkinab [10]

The Answer Divided Would Give You 11411.4832536.

When You Round This Answer Then You Would Get 11,000 Rounded To The Nearest Thousandth. This Is What I Think The Answer Is.

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3 years ago

Find the dimensions of a rectangle with perimeter 112 m whose area is as large as possible. step 1 if a rectangle has dimensions

Veronika [31]

Please use the solution below:
Let P = perimeter, A = area
As provided above, a = xy and
We know that the formula to solve for the perimeter of a rectangle is P = 2x + 2y. Using the given 112m, we can solve the perimeter using the formula:
112 = 2x + 2y
56 = x + y

x = 56-y or y = 56-x
Let's solve the perimeter in terms of y using the formula below:
A = (56-y)(y)
Find the derivative of A = 56-y^2 to get the value of y.
dA/dy = 56-2y = 0
y = 56/2
y = 28
To find X, substitute the value of y in the equation x = 56 - y.
x = 56 - 28
Therefore, x = 28.
We can conclude that the figure is not a rectangle but a square.

7 0

3 years ago

Just need help with #2

Bond [772]

The known is the mass of 163 grams and the unknown is the volume

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4 years ago

WILL CHOOSE BRAINLIEST PLZ HELP!

mario62 [17]

Answer:

R'(-1,3) , S'(0,2) , T'(-1,1), U'(-3,1)

Step-by-step explanation:

To find the vertices of a point after a dilation simply multiply the x and y values of each given coordinate by the scale factor.

So to find the vertices of Trapezoid RSTU after a dilation centered at the origin with a scale factor of 1/5 we would multiply the x and y values of the given coordinates of Trapezoid RSTU by 1/5.

Given Coordinates: R(-5, 15), S(0, 10), T(-5, 5) and U(-15, 5)

Scale Factor: 1/5

R(-5, 15) -----> ( -5 * 1/5 = -1 , 15 * 1/5 = 3 ) -----> (-1,3)

S(0,10) -----> ( 0 * 1/5 = 0 , 10 * 1/5 = 2 ) -----> (0,2)

T(-5,5) -----> ( -5 * 1/5 = -1 , 5 * 1/5 = 1 ) -----> (-1,1)

U(-15,5) -----> (-15 * 1/5 = -3 , 5 * 1/5 = 1 ) -----> (-3,1)

So the coordinates of Trapezoid RSTU after a dilation with a scale factor of 1/5 are R'(-1,3) , S'(0,2) , T'(-1,1), U'(-3,1)

Refer to the attached image for more validation

4 0

3 years ago

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