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Blababa [14]
2 years ago
5

Brainliest if correct Solve: 8( 4 - 2^{6} divided by 4)

Mathematics
1 answer:
polet [3.4K]2 years ago
6 0

\huge\text{Hey there!}

\mathsf{\dfrac{8(4 - 2^6)}{4}}

\mathsf{2^6}\\\mathsf{\rightarrow2\times2\times2\times2\times2\times2}\\\mathsf{\rightarrow 4\times4\times4}\\\mathsf{\rightarrow 16\times4}\\\mathsf{\rightarrow \bf 64}

\mathsf{= \dfrac{8(4 - \bf 64)}{4}}

\mathsf{4 - 64}\\\mathsf{\rightarrow \bf -60}

\mathsf{= \dfrac{8(\bf -60)}{4}}

\mathsf{8(-60)}\\\mathsf{\rightarrow \bf -480}

\mathsf{= \dfrac{-480}{4}}\\\\\mathsf{\rightarrow \dfrac{-480\div4}{4\div4}}\\\\\mathsf{\rightarrow- \dfrac{\bf 120}{1}}\\\\\mathsf{\rightarrow \bold{-120}\div 1}}\\\\\mathsf{\rightarrow \bf -120}

\huge\text{Therefore, your answer is: \boxed{\mathsf{-120}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

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13,841,287,201

Step-by-step explanation:

simply the parenthesis:

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5 0
3 years ago
Prove that a triangle with the sides a - 1 cm to root under a ​
vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.  

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm  

Hence,

{AB}^2 = (a -1)^2 

Now We know that

(a- b)^2 = a^2+b^2 - 2ab

So;

{AB}^2= a^2 + 1^2 -2\times a \times1

{AB}^2 = a^2 + 1 -2a

Now;

{BC}^2 = (2\sqrt{a})^2= 4a

Also;

{CA}^2 = (a + 1)^2

Now We know that

(a+ b)^2 = a^2+b^2 + 2ab

{CA}^2= a^2 + 1^2 +2\times a \times1

{CA}^2 = a^2 + 1 +2a

{CA}^2 = AB^2 + BC^2

[By Pythagoras theorem]

a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a

Hence, {CA}^2 = AB^2 + BC^2

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0
3 years ago
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