No, this is not true every time. It depends on the conditions given.
For example-
Suppose we have a Box A with dimensions 10 x 10 x 1 and Box B with dimensions 5 x 5 x 5.
Box B has a surface area = 2(25+25+25) = 150 and a volume of 5*5*5= 125 cubic units
Box A has a larger surface area = 2(100+10+10) = 240 and a smaller volume = 10*10*1 = 100 cubic units
Similarly take an example of sphere.
Lets suppose the radius of the sphere is 2 cm
So, SA is 4πr² = 4*3.14*2*2 = 50.24 cm²
Volume of the sphere is = 4πr³ /3 = 33.50 cm³
Here also the SA is greater.
Answer:
16+2=18
18-3=15
2*3=6
Step-by-step explanation:
Hope this answers your question :)
9514 1404 393
Answer:
- red division: 6 teams
- blue division: 5 teams
Step-by-step explanation:
We can let r and b represent the numbers of teams in the red and blue divisions, respectively. The total number of goals scored in each division will be the average for that division times the number of teams in that division.
r - b = 1 . . . . . . there is 1 more red team than blue
4.5r +4.2b = 48 . . . . . . total goals scored per week
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Solving by substitution, we have ...
r = b +1
4.5(b +1) +4.2b = 48 . . . . substitute for r
8.7b +4.5 = 48 . . . . . . . . simplify
8.7b = 43.5 . . . . . . . . . . subtract 4.5
b = 43.5/8.7 = 5 . . . . . divide by 8.7
r = b +1 = 6 . . . . . . . . . find r
There are 6 red teams and 5 blue teams.
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<em>Additional comment</em>
The basic idea is that you make an equation for each relation given in the problem statement. For a problem like this, you do need to have an understanding of how the average number of goals would be calculated and how that relates to the total goals.
