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2 years ago

Someone help please i don’t want to fail math

Mathematics

1 answer:

VladimirAG [237]2 years ago

5 0

Answer:

Image below!

Step-by-step explanation:

Plotting $\underline{y=2x+3}$

Step 1: determine the y-intercept

$(0,3)$

plot the point as the first point on the graph

Step 2: Move 2 units up, and 1 unit left (keep repeating this process until you have reached the limit of the graph)

Step 3: Go to the other side of the graph of the first point (y-intercept)

move 2 units down, and 1 unit right keep repeating this process until you have reached the limit of the graph)

When you've completed this process, it should look like this:

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The amount of mustard dispensed from a standard dispenser is normally distributed with a mean of 0.9oz and a variance of 0.01oz.

lubasha [3.4K]

Answer:

the probability that more than 3 of them will have more than one ounce of mustard is 0.05975

Step-by-step explanation:

Given te data in the question;

let x rep the quantity of mustard on a hotdog ( in oz)

X → N ( u = 0.9, α² = 0.01 )

now P( more than one ounces of mustard on a hotdog) will be

P( X>1 ) = P( Z > ((1-0.9)/(√0.01)) ) = P( Z > 1 ) = 1 - P( Z < 1 )

= 1 - 0.84134 = 0.15866

Also let Y rep the number of hotdogs that have more than one ounces of mustard, so

Y → Bin( n = 10, p = 0.15866 )

P( y = y ) = (¹⁰ _y) ( 0.15855)⁰ ( 1 - 0.15866 )^10-y, y = 0,1,2,3......, 10

so required probability = P(Y > 3) = 1 - P(Y ≤ 3)

= 1 - P(Y=0) - P(Y=1) - P(Y=2) - P(Y=3)

=1 - (¹⁰ ₀) ( 0.15855)⁰ (1 - 0.15855)¹⁰⁻⁰ - (¹⁰ ₁) ( 0.15855)¹ (1 - 0.15855)¹⁰⁻¹ - (¹⁰ ₂) ( 0.15855)² (1 - 0.15855)¹⁰⁻² - (¹⁰ ₃) ( 0.15855)³ (1 - 0.15855)¹⁰⁻³

= 0.05975

Therefore the probability that more than 3 of them will have more than one ounce of mustard is 0.05975

4 0

3 years ago

The average age of residents in a large residential retirement community is 69 years with standard deviation 5.8 years. A simple

frosja888 [35]

Answer:

a. of the central limit theorem.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size, larger than 30, can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

In this problem, the sample size is 100, so it is sufficiently large to use the Central Limit Theorem. The mean of the sample in 69 and the standard deviation of the sample is 0.58.

So the correct answer is:

a. of the central limit theorem.

4 0

3 years ago

there were 600 sheep and goats in the hills if the ratio of sheep to goats is 1 to 2 how many are sheep.

larisa86 [58]

Answer:

i think the sheep is 300 because 600 divide by 2 is 300.

5 0

3 years ago

Read 2 more answers

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