Answer:
B
Step-by-step explanation:
Reflection is a transformation that preserves lengths.
Triangle XYZ, with side lengths XY = 7 in, YZ = 5 in, XZ = 4 in, is reflected across the x-axis to result in △X'Y'Z'.
This means that corresponding sides have the same lengths:
- XY = X'Y' = 7 in;
- XZ = X'Z' = 4 in;
- YZ = Y'Z' = 5 in.
Find the perimeters of both triangles:

Hence, only option B is true.
Answer:
17,511,005
Step-by-step explanation:
Your welcome
Answer:
1, 2, 3, 4
Step-by-step explanation:
- 4 1/3·1 = 4 1/3 Good
- 7 1/3·2 2/5 = 22/3·12/5 = 110/15·36/15= 3960/225 = 17 3/5 Good
- 6 2/3·1/2 = (6 2/3)/2 = 3 1/3 Good
- 4 1/2·2 1/6 = 9/2·13/6 = 27/6·13/6 = 9 3/4 Good
- 5·3 1/4 = 20/4·13/4 = 16 1/4 Doesn't Work
N₁*$0.10 + n₂*$0.25 = $2.25
n₁ + n₂ = 12
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This means that:
n₁ = 12 - n₂
And:
(12 - n₂)*$0.10 + n₂*$0.25 = $2.25
12*$0.10 - n₂*$0.10 + n₂*$0.25 = $2.25
$1.20 + n₂*$0.05*(5-2) = $2.25
$1.20 + n₂*$0.05*3 = $2.25
$1.20 + n₂*$0.15 = $2.25
n₂*$0.15 = $2.25 - $1.20
n₂*$0.15 = $1.05
n₂ = ($1.05)/($0.15)
n₂ = 7
If n₂ = 7:
n₁ + 7 = 12
Therefore, n₁ = 5.
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Answer:
5 dimes and 7 quarters.
The slope of the line is: y= 2x+2