The absolute value makes it 9
Add a point at (0.-2) then go down 3 and put another point connect the dots thats it
Step-by-step explanation:
Answer:
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Step-by-step explanation:
Answer:

Step-by-step explanation:
Given equation:

Cube root both sides:
![\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%5B3%5D%7Bp%5E3%7D%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B1%7D%7B8%7D%7D)
![\implies p= \sqrt[3]{\dfrac{1}{8}}](https://tex.z-dn.net/?f=%5Cimplies%20p%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B1%7D%7B8%7D%7D)
![\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:](https://tex.z-dn.net/?f=%5Ctextsf%7BApply%20exponent%20rule%7D%20%5Cquad%20%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%3A)





Rewrite 8 as 2³:



Simplify:



Answer:
The inverse of this equation would be y =
Step-by-step explanation:
To find the inverse of any equation, start by switching the y and x values. Then solve for the new y value. That equation will be your inverse.
y = 7x^2 - 3
x = 7y^2 - 3
x + 3 = 7y^2
= y^2
= y