Answer:
The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft
Step-by-step explanation:
Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²
For maximum volume, the side length, s of the cube must all be equal ;
Therefore area of one side = s²
Number of sides in a cube with top open = 5 sides
Area of surface = 5 × s² = 180
Therefore s² = 180/5 = 36
s² = 36
s = √36 = 6 ft
Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.
(1/3)x=3+(1/4)x
is the same as
(4/12)x=(36/12)+(3/12)x
subtract the 3/12x from each side
(1/12)x=36/12
multiply by 12 on each side
x=36
Answer:
-1.99, 1.99
Step-by-step explanation:
Use a table to find the z-scores.
For the first z-score:
P(x < z) = 0.0233
z = -1.99
For the second z-score:
P(x > z) = 0.0233
P(x < z) = 1 − 0.0233 = 0.9767
z = 1.99
Answer: 50%
Step-by-step explanation: The customer paid half of what the shirt was originally for, so its 50% or "half" off.
Answer:
Below.
Step-by-step explanation:
a) 5x-x² = x(5 - x).
b) x²-6x-27 = (x - 9)(x + 3).
c) x²+x-56 = (x - 7)(x + 8).
d) x³+8 = (x + 2)(x^2 - 2x + 4)
e) 3x⁴-54t = 3(x^4 - 18t)
f) x²+3x-10 = (x - 2)(x + 5)
g) 2(x⁴+x³-12x²) = 2x^2(x + 4)(x - 3)
h) 20(x³-1) = 20(x - 1)(x^2 + x + 1)
