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3 years ago

What percentage of the questions did he get right

Mathematics

2 answers:

Wittaler [7]3 years ago

8 0

Answer: 75% 45/60 is .75 witch is 75%

Step-by-step explanation:

Ann [662]3 years ago

5 0

Probably d. 75% I don’t know how to explain it other than divide 45 by 60

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A metal plate is 8.431 centimeters wide. Which is this measure written in word form?

vagabundo [1.1K]

Answer:

Eight and one hundred thirty-four thousandths

Step-by-step explanation:

Thats how u write it in word form! i hope this helped :)

6 0

3 years ago

The common ratio in a geometric series is 0.50.50, point, 5 and the first term is 256256256.

V125BC [204]

Answer:

504

Step-by-step explanation:

I think the correct question is like:The common ratio in a geometric series is 0.50 ( point 5) and the first term is 256.

Find the sum of the first 6 terms in the series.

If it's right, then

Sₙ = (a₁ * (1 - rⁿ)) / (1 - r)

S₆ = (256 * ( 1 - 0.5⁶)) / (1 - 0.5) = (256 * 0.984375) / 0.5 = 504

6 0

3 years ago

PLEASE HELP!!!!!!!!!!!!

Igoryamba

<h3>Answer: 21x+14 (choice A)</h3>

Explanation:

Use the distribution rule to multiply the outer 7 by each term inside

7 times 3x = 21x
7 times 2 = 14

We go from 7(3x+2) to 21x+14

3 0

3 years ago

Read 2 more answers

Factor the greatest common factor from the polynomial 3x^2 + 6x -9

ryzh [129]

Answer:

$3(x+3)(x -1)$

Step-by-step explanation:

$3x^2 + 6x -9$

All the terms in this polynomial are divisible by 3. Factor 3 out of this polynomial:

$= 3(x^2 + 2x -3)$

Now, factor inside the parentheses by grouping:

$= 3(x^2 -1x+3x -3)$

We knew to split the +2x up into -1x and 3x because -1 and 3 multiply to get -3, which is the last value in the polynomial.

$= 3(x(x -1)+3(x -1))\\= 3(x+3)(x -1)$

Therefore, the final factored polynomial is $3(x+3)(x -1)$ .

4 0

2 years ago

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$

Thus, the required solution is

$y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.$

6 0

3 years ago