Q55.
UTA+ATS=UTS
x+18+120=12x+17
x+138=12x+17
12x-x=138-17
11x=121
x=121/11
x=11
mUTA=x+18
put the value of x
11+18
mUTA=29
Q57.
AQP+RQA=RQP
9x+2+75=1+28x
9x+77=1+28x
28x-9x=77-1
19x=76
x=76/19
x=4
mRQP=1+28x
put the value of x
1+28(4)
1+112
mRQP=113
Answer:
18.
Step-by-step explanation:
1) formula of the perimeter given in the condition is:
p=2(VW+XV) or p=2(VY+XY).
Note, VW=XY and XV=VY;
2) if to substitute p=84, VW=2z+2 and XV=3z into the formula above, then
2(2z+2+3z)=84, ⇔ 5z+2=42; ⇒ z=8.
3) if z=8, then VW=2z+2=2*8+2=18.
All positive numbers and zero. All positive numbers because any value that is absolute becomes positive.
I would say the answer is E. The coach cannot select those he observes. the reason being is because all people can run a different time due to the age of the person, not saying that they have a limit but the question leaves out how fit the player is. to put in words a athletic person on the average could run about 4-5 laps depending on how far each lap is. Hope that helps
