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4 years ago

If csc theta =sqrt5/15 find sin theta

1 answer:

5 0

The cosecant is the reciprocal of the sine, so

$\sin \theta = \dfrac{15}{\sqrt{5}} = 3 \sqrt{5}$

That's not the sine of a real angle because it's out of the range -1 to 1.

You might be interested in

What are the x-intercepts of the function f(x) = –2x2 – 3x + 20?

Bumek [7]

If you would like to find the x-intercepts of the function f(x) = - 2 * x^2 - 3 * x + 20, you can calculate this using the following steps:

f(x) = - 2 * x^2 - 3 * x + 20
f(x) = - (2x - 5) * (x + 4)
1. x = - 4
2. x = 5/2

(x, y) = (-4, 0)

The correct result would be (-4, 0).

6 0

3 years ago

Read 2 more answers

What is the slope of a line perpendicular to the line whose equation is

Marina86 [1]

Answer:

The slope of a line perpendicular to the line whose equation is 4x - 5y = 10 is -5/4.

Step-by-step explanation:

provided the equation;

4x- 5y=10.(let it be equation of line1 )

and the other line be line2

from perpendicularty principle

M1×M2= -1

BUT for M1(slope of line L1)

y= mx+c

where "c" is constant value.

"m" is slope.

therefore

5y= 4x - 10

(dividing by five throughout)

y=(4x/5) - 2

y= (4/5)x - 2

therefore M1= (4/5)

Returning back to our principle

M1×M2= -1

(4/5)M2=-1

M2= -5/4

3 0

3 years ago

Peter babysits his sister on Monday and Friday. He babysits for his neighbor 40% of the days Monday through Friday. He babysits

saul85 [17]

Answer:

Question 1: False

Question 2: True

Question 3: True

Question 4: False

Step-by-step explanation:

Peter babysits his sister 2 days: Monday and Friday.

He babysits for his neighbor 40% of the time between Monday through Friday. This includes 5 days. 40% of 5days = 2 days.

On the weekend, Peter babysits 50% of the days. There are 2 days in the weekend

50% × 2 days = 1 day.

Question 1: False

Altogether, Peter babysits 5 days every week.

Question 2: True

Question 3: True

Peter babysits 4 out 5 days during Monday-Friday 4/5= 80%

Question 4: False

Peter babysits 5 days out of 7 during the week. 5/7 = 71% of the days, which is less than 90%

5 0

4 years ago

Suppose you have a bag containing 15 red beads, 12 white beads and 8 black beads. You are going to draw one bead out of the bag.

iren [92.7K]

Answer:

probability that you draw a black bead or a white bead that is P(E1 U E2)

= 20/35 = 0.571

Step-by-step explanation:

Given a bag containing 15 red beads, 12 white beads and 8 black beads

n(S) = 15 + 12 +8 = 35

Let 'E1 be the event of selecting black beads and E2 be the event of selecting white beads

n(E1) = 8 and n(E2) = 12

Probability of draw a black bead P( E1 ) = $\frac{n(E_{1} )}{n(S)}$

$P(E_{1}) = \frac{8}{35}$

Probability of draw a white bead P( E2 ) = $\frac{n(E_{2} )}{n(S)}$

$P(E_{2}) = \frac{12}{35}$

probability that you draw a black bead or a white bead that is P(E1 U E2)

and E1 n E2 = ∅ (disjoint events)

Axiom of union

$P(E_{1}UE_{2} ) = P(E_{1})+P(E_{2}) - P(E_{1}nE_{2})\\$

E1 n E2 = ∅ ⇒ P(E1 n E2) = p(∅) = 0

$P(E_{1}UE_{2} ) = P(E_{1})+P(E_{2}) - 0$

$P(E_{1}UE_{2} ) = \frac{8}{35} +\frac{12}{35}$

$P(E_{1}UE_{2} ) = \frac{20}{35}$

$P(E_{1}UE_{2} ) = 0.571$

8 0

4 years ago

A reacher deposited Rs 66000 in his/her saving account for as many years as the rate of interest per annum .If he/ she received

natali 33 [55]

Answer:

Time and rate is 4 years and 4% respectively.

Step-by-step explanation:

P = Rs 66000

T = R

I = 10560

I = PTR/100

Rs 10560 = (66000*T^2)/100

or, Rs 1056000 = 66000*T^2

or. 1056000/66000 = T^2

or, 16 = T^2

OR, T =√16

so T = 4

Then

T = R

so, R = 4

6 0

3 years ago